Total weight decreased = 6*3= 18 kg
New man weight = (80-18) = 62 kg.
Workspace
NA
SHSTTON
83
Solv. Corr.
108
Solv. In. Corr.
191
Attempted
3 M:38 S
Avg. Time
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A car averages 55 mph for the first 4 hours of a trip and averages 70 mph for each additional hour. The average speed for the entire trip was 60 mph. How many hours long is the trip?
Lets assume additional hours = x hrs.
So total No. hours in journey = (4+x)
[(55*4)+(70*x)]/(4+x)=60 =>
=>x=2
Therefore, Total No. of hrs. in Journey = (x+4) = 6 hrs.
Workspace
NA
SHSTTON
59
Solv. Corr.
51
Solv. In. Corr.
110
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0 M:58 S
Avg. Time
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The average number of visitors of a library in the first 4 days of a week was 58. The average for the 2nd, 3rd, 4th and 5th days was 60.If the number of visitors on the 1st and 5th days were in the ratio 7:8 then what is the number of visitors on the 5th day of the library?
If number of visitors on 1st, 2nd, 3rd, 4th & 5th day are a, b, c, d & e respectively, then
a+b+c+d=58*4=232 ----(i)
b+c+d+e=60*4=240 ----(ii)
Subtracting eq. (i) from (ii)
e-a=8 ---(iii)
Given, a/e=7/8 ---(iv)
So from eq. (iii) & (iv)
a=56, e=64
Workspace
NA
SHSTTON
47
Solv. Corr.
44
Solv. In. Corr.
91
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0 M:0 S
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The average age of 10 members of a committee is the same as it was 4 years ago, because an old member has been replaced by a young member. Find how much younger is the new member?
Lets assume the average of all 10 members 4 years ago = x years.
After 4 years, 10 members age increases by 10*4 = 40 years.
Conditon given: There is no change in the average as a person is replaced by an younger one.
=> The younger one age is 40 years less than the old one.
Workspace
NA
SHSTTON
405
Solv. Corr.
592
Solv. In. Corr.
997
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In a test called ACSAT, the average marks of the 15 test takers is 240. If the marks of 5 test takers are subtracted , the average marks decreases by 40 . What is the average marks of 5 test takers ?
Total of 15 students = 3600
Total of 10 students = [(240-40) * 10 ] = 2000
Total of 5 students = (3600 - 2000) = 1600
Avg of 5 students = 1600/5 = 320
Workspace
NA
SHSTTON
9
Solv. Corr.
20
Solv. In. Corr.
29
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1 M:46 S
Avg. Time
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A man employs 20 men, 15 women and x children. he pays daily wages of Rs. 10 per men Rs. 8 per women and Rs. 4 per chil his daily average wages bill works out to Rs. 8.50 per person. What the value of x?
Series is divided into two terms 1,3,5….. will contain 100 terms
and second series is -2 ,-4,-6
S=n/2*(2a+(n-1)d)
First series give s=10000
Second series give s=-10100
so total = (10000 - 10100) = 100
so avg. = -100/200 = -0.5
Workspace
NA
SHSTTON
17
Solv. Corr.
9
Solv. In. Corr.
26
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A student's average ( arithmetic mean) test score on 4 tests is 78. What must be the students score on a 5th test for the students average score on the 5th test to be 80?
Total scores of 4 test = 78 * 4 = 312
Total scores of 5 tests = 80 * 5 = 400
So, 5th test score = (400-312)=88
Workspace
NA
SHSTTON
6
Solv. Corr.
25
Solv. In. Corr.
31
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0 M:0 S
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The price of lunch for 15 people was 207 pounds, including a 15 percent gratuity of service. What was the average price per person, excluding the gratuity?
Let the net price excluding the gratuity of service = x pounds
Then, total price including 15% gratuity of service = x*(100+15100) = 1.15x pounds
So, 1.15x = 207 pounds
=> x = 207/1.15 = 180 pounds
Net price of lunch for each person = 180/15 = 12 pounds
Workspace
NA
SHSTTON
12
Solv. Corr.
14
Solv. In. Corr.
26
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0 M:0 S
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The average of run recorded by 8 players is 40. If the average of the runs by the first five players is 39, and that of the last four players is 34, what is the number of runs recorded by the fifth player?
Total run recorded by 8 players = 80*4 = 320
Total run by first five players = 5 * 39 = 195
Total run by four players = 4*34 = 136
Run record of fifth player = (195+136-320) = 11
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