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Write a program using command line arguments to input a number and find that number is even or odd.
INPUT: 14
OUTPUT: Even
INPUT: 13
OUTPUT: Odd
Answer:
#include
int main(int argc,char *argv[])
{
int i;
if(argc==2)
{
if(atoi(argv[1])%2==0)
printf("\nEVEN NO.\n");
else
printf("\nODD NO.\n");
}
else if(argc>2)
printf("\nEnter only one Integer..!!!\n");
else
printf("\nEnter one Integer.!!!\n");
return 0;
}
Asked In ::
Language:
Sumit
27 Oct, 2017 12:42 AM
#include<stdio.h>
int main(int argc,char *argv[])
{
int i;
if(argc==2)
{
if(atoi(argv[1])%2==0)
printf("\nEVEN NO.\n");
else
printf("\nODD NO.\n");
}
else if(argc>2)
printf("\nEnter only one Integer..!!!\n");
else
printf("\nEnter one Integer.!!!\n");
return 0;
}
Language:
Siddhartha Paul
19 Jun, 2019 2:16 PM
import java.util.*;
public class EvenOdd
{
public static void main(String []args)
{
int num;
System.out.println("Enter a number: ");
num=Integer.parseInt(args[0]);
if(num % 2 == 0)
System.out.println(num+" is even!");
else
System.out.println(num+" is odd!");
}
}
