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9. How to implement sizeof operator.

Answer:

#define my_sizeof(type) (char *)(&type+1)-(char*)(&type)
int main()
{
    double x;
    printf("%d", my_sizeof(x));
    getchar();
    return 0;
}

Amit
29 Aug, 2018 4:40 PM

#define my_sizeof(type) (char *)(&type+1)-(char*)(&type)
int main()
{
    double x;
    printf("%d", my_sizeof(x));
    getchar();
    return 0;
}

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