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Stacks Questions

Home > Technical Aptitude > Data Structures > Stacks > General Questions
NA
SHSTTON
35
Solv. Corr.
42
Solv. In. Corr.
77
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61 / 93

Choose the correct option.

The equivalent infix expression and value for the postfix form 1 2 + 3 * 4 5 * – will be ___________


A(2 + 1) * (3 – 4) * 5 and 13

B1 + 2 * 3 – 4 * 5 and -13

C(1 + 2) * 3 – (4 * 5) and -11

D1 + 2 * (3 – 4) * 5 and -11

Answer: Option C

Explanation:

Given postfix expression : 1 2 + 3 * 4 5 * –
⇒ (1 + 2) 3 * 4 5 * –
⇒ ((1 + 2) * 3) 4 5 * –
⇒ ((1 + 2) * 3) (4 * 5) –
⇒ ((1 + 2) * 3) – (4 * 5)
So, the equivalent infix expression is (1 + 2) * 3 – (4 * 5) and it's value is -11.

Workspace

NA
SHSTTON
40
Solv. Corr.
49
Solv. In. Corr.
89
Attempted
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Avg. Time

62 / 93

Choose the correct option.

What is the value of the postfix expression 2 3 + 4 5 6 – – *


A21

B19

C25

D-4

Answer: Option C

Explanation:

Given postfix expression : 2 3 + 4 5 6 – – *
infix ⇒ (2 + 3)4 (5 – 6) – *
⇒ (2 + 3)*4 – (5 – 6)
Hence, value = (2 + 3) * (4 – (5 – 6)) = 5 *(4 – (-1)) = 5*5 = 25.

Workspace

NA
SHSTTON
34
Solv. Corr.
31
Solv. In. Corr.
65
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63 / 93

Choose the correct option.

What would be the Prefix notation for the given equation?

A+B*C^D


A+A^B*CD

B+A*B^CD

C^A*B+CD

D*A+B^CD

Answer: Option B

Explanation:

Reverse the equation or scan the equation from right to left. Apply the infix-prefix algorithm. The preference order in ascending order are as follows +*^. Operators are pushed into the stack and popped if its preference is greater than the one which is getting pushed. In the end all operators are popped. The equation evaluates to DC^B*A+. Reversing this we get our following answer.

Workspace

NA
SHSTTON
32
Solv. Corr.
62
Solv. In. Corr.
94
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64 / 93

Choose the correct option.

An error is thrown if the character ‘\n' is pushed in to the character stack.


ATRUE

BFALSE

Answer: Option B

Explanation:

The input character ‘\n' is accepted as a character by the evaluation of prefix expression algorithm.

Workspace

NA
SHSTTON
38
Solv. Corr.
40
Solv. In. Corr.
78
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65 / 93

Choose the correct option.

Using the evaluation of prefix algorithm, evaluate +-9 2 7.


A4

B10

C14

D17

Answer: Option C

Explanation:

Using the evaluation of prefix algorithm, +-9 2 7 is evaluated as 9-2+7=14.

Workspace

NA
SHSTTON
47
Solv. Corr.
61
Solv. In. Corr.
108
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66 / 93

Choose the correct option.

Out of the following operators (^, *, +, &, $), the one having highest priority is _________


A$

B

C&

D^

Answer: Option D

Explanation:

According to the algorithm (infix-prefix), it follows that the exponentiation will have the highest priority.

Workspace

NA
SHSTTON
24
Solv. Corr.
39
Solv. In. Corr.
63
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67 / 93

Choose the correct option.

The prefix expression of the postfix expression AB+CD-* is __________


A+AB*-CD

B(A+B)*(C-D)

C*+AB-CD

DA+*BCD-

Answer: Option C

Explanation:

To convert from postfix to prefix, we first convert it to infix and then to prefix.
postfix : AB+CD-*
infix ⇒ (A+B) * (C-D)
So, prefix ⇒ +AB*-CD,
⇒ *+AB-CD.
Therefore, correct choice is *+AB-CD.

Workspace

NA
SHSTTON
93
Solv. Corr.
14
Solv. In. Corr.
107
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68 / 93

Choose the correct option.

What is the time complexity of an infix to postfix conversion algorithm?


AO(N)

BO(N log N)

CO(M log N)

DO(N2)

Answer: Option A

Explanation:

The time complexity of an infix to postfix expression conversion algorithm is mathematically found to be O(N).

Workspace

NA
SHSTTON
14
Solv. Corr.
44
Solv. In. Corr.
58
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69 / 93

Choose the correct option.

What is the postfix expression for the corresponding infix expression?

a+b*c+(d*e)


Aabc+*de*+

Babc*+de*+

Cabc*+(de)*+

Da+bc*de+*

Answer: Option B

Explanation:

Using the infix to postfix expression conversion algorithm, the corresponding postfix expression is found to be abc*+de*+.

Workspace

NA
SHSTTON
49
Solv. Corr.
41
Solv. In. Corr.
90
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Choose the correct option.

Parentheses are simply ignored in the conversion of infix to postfix expression.


ATRUE

BFALSE

Answer: Option B

Explanation:

When a parenthesis is encountered, it is placed on the operator stack. When the corresponding parenthesis is encountered, the stack is popped until the other parenthesis is reached and they are discarded.

Workspace

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