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1. A train 575 m long crosses a tunnel of length 325 in 90 sec. What is the speed of the train in kmph.
Answer: Option C
Explanation:Total distance traveled = Length of train + Length of tunnel
= 575 + 325 = 900.
Time taken to cross the tunnel = 90 sec.
Speed in kmph = distance/time * 18/5 = 900/90 * 18/5 = 180/5 = 36 kmph.
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2. Three partner's A,B,C start a business. Twice A's capital is equal to thrice B's capital and B's capital is four times C's capital. Out of a total profit of Rs.16500 at the end of the year, B's share is:
Answer: Option B
Explanation:Let C = x.
Then B = 4x and 2A = 3 * 4x = 12x. or A = 6x.
Therefore, A : B : C = 6x : 4x : x = 6 : 4 : 1.
Therefore, B's capital = Rs. 16500 * 4/11= Rs.6000.
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3. The probability that a number selected at random from first 50 natural numbers is a composite number is
Answer: Option B
Explanation:The number of exhaustive events = 50C1 = 50.
We have 15 primes from 1 to 50.
Number of favourable cases are 34.
Therefore, Required probability = 34/50 = 17/25.
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4. Two pipes A and B together can fill a cistern in 4 hours. Had they been opened separately, then B would have taken 6 hours more than A to fill the cistern. How much time will be taken by A to fill the cistern separately?
Answer: Option C
Explanation:Let the cistern be filled by pipe A alone in x hours.
Then, pipe B will fill it in (x + 6) hours.
.'. 1/x + 1/(x + 6) = 1/4
=> (x + 6 + x)/x(x + 6)= 1/4
=> x^2 - 2x - 24 = 0.
=> (x -6)(x + 4) = 0.
=> x = 6. [neglecting the negative value of x]
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5. An article is sold at a certain price. By selling it at 2/3 of that price one loses 10%. Find the gain percent at original price.
Answer: Option B
Explanation:Let the original S.P be Rs. X.
Then new S.P = Rs. (2/3)X, Loss =10%
So, C.P = Rs. [100/90 * (2/3)X ] = 20X/27.
Now C.P = Rs. 20X/27, S.P =Rs. X.
Gain = Rs. [ X -20X/27 ] =Rs.7X/27.
Hence, Gain % = [ 7X/27 *27/20X *100 ]% = 35%.
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6. A lent Rs. 5000 to B for 2 years and Rs. 3000 to C for 4 years on simple interest at the same rate of interest and received Rs. 2200 in all from both of them as interest. The rate of interest per annum is:
Answer: Option D
Explanation:Let the rate be R% p.a.
Then, (5000 x R x 2)/100 + (3000 x R x 4)/100 = 2200.
=> 100R + 120R = 2200
=> R = 2200/220 = 10.
.'. Rate = 10%.
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7. In a group of donkeys and pigs, the numbers of legs are 16 more than twice the number of heads. The number of donkeys is
Answer: Option B
Explanation:Let the number of donkeys be x and the number of pigs be y.
Then,
=> 4x + 2y = 2(x + y) = 16.
=> 2x + (2x + 2y) = (2x + 2y) + 16.
=> x = 8.
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8. The average age of five girls 11.The oldest among them is 15 years old.What is the average of the others?
Answer: Option C
Explanation:Let 'T' be the total age of 5 girls.
Then, T/5 = 11.
=> T = 55.
Given, Age of the Oldest girl = 15.
Then, Total age of other 4 girls will be 55-15=40.
So, Avg. of other 4 girls 40/4 = 10.
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9. What must be added to the two numbers, which are in ratio 5 : 12, so that the new ratio becomes 3:4?
Answer: Option D
Explanation:Let x be the required number.
Then, According to the question,
=> (5+x)/(12+x) = 3/4
=> 20 + 4x = 36 + 3x.
=> x = 16.
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10. Today, the age of a father is thrice the age of his son. Ater 5 years the age of father will be 2.5 times the age of his son. What is the age of son today?
Answer: Option B
Explanation:Let the age of son = S years and the age of father = F years.
According to the question,
=> F = 3*S.
=> F = 3S.
After 5 years,
=> (F+5) = 2.5 * (S+5).
=> 3S + 5 = 2.5S + 12.5 [put F=3S]
=> 0.5S = 7.5
=> S = 15
Hence, the age of son = 15 years.
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Here is the list of questions asked in iGate model papers for freshers iGate online test questions. Practice iGate Written Test Papers with Solutions and take Q4Interview iGate Online Test Questions to crack iGate written round test. Overall the level of the iGate Online Assessment Test is moderate. Only those candidates who clear the written exam will qualify for the next round, so practic all the questions here and take all the free tests before going for final selection process of iGate