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61 / 146
In a election between two candidate 10% of votes were invalid winner got 70% of valid votes and was elected by a majority of 900 votes. find the total number of votes?
A2600
B2200
C2500
D2550
Answer: Option C
Explanation:Lets assume votes = x
valid votes are 0.9x,
Given 70% of 0.9x is 900 more than 30% of 0.9x,
=> 0.9*0.7-900=0.3*0.9x
=> x=2500
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62 / 146
log base 12 144p=3 then p= ?
A12
B13
C15
D11
Answer: Option A
Explanation:log base 12 144p=3
=> 144p=12^3
=> 144p=12^2 *12
=> 144p=144*12
=> p=12
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63 / 146
3 men and 8 women complete a task in same time as 6 men and 2 women do. How much fraction of work will be finished in same time if 4 men and 5 women will do that task.
A6/ 13
B7/11
C13/14
D11/12
Answer: Option C
Explanation:3M + 8W = 6M + 2W ---------(1)
solving this we get
M = 2W
Therefore 3M + 8W = 14W
4M + 5W =13W
=>fraction of work is 13/14
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64 / 146
The sum of ages of suresh and his father is 78 years.6 years hence father's age will be twice of suresh's age. Find present age of father.
A54 years
B45 years
C55 years
DNone of these
Answer: Option A
Explanation:Lets assume suresh age = x years.
So, father age = (78-x) years.
Condition : 6 years hence
2* (x + 6) = (78 - x + 6)
=> 2x + 12 = 84 - x
=> 3x = 72
x = 24 years.
Father age = 78 - 24 = 54 years.
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65 / 146
In this question A^B means A raised to the power of B Start with the integers from 1 to 10^2012. Replace each of them by the sum of its digits to get a string of 10^2012 numbers. Keep doing this until you get 10^2012 single digit numbers. Let m be the number of 1's and n be the number of 2's. Then m - n
A1
B2
C3
D0
Answer: Option A
Explanation:We divide all the numbers into groups of 9. (1 to 9), (10 to 18).....
Now when we divide each term in the first group by 9, we get 1, 2, 3 ..0 as remainders. Now digit sum is nothing but finding remainder when a number is divided by 9. So the last term, 10^2012 gives remainder 1 when divided by 9. So there is one "1" extra than 2's.
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66 / 146
Two trains A and B start simultaneously from stations X and Y towards each other respectively. After meeting at a point between X and Y,train A reaches station Y in 9 hours and train B reaches station X in 4 hours from the time they have met each other. If the speed of trainA is 36 km/hr, what is the speed of train B?
A24 km/hr
B54 km/hr
C81 km/hr
D16 km/hr
Answer: Option B
Explanation:Naming the trains as A and B. Then,
(A's speed) : (B's speed) = (b : a)^.5
where b and a is the time taken by trains B and A, to reach their destination after they meet.
hence,
36/B's speed = (4: 9)^.5
=> B's speed = 54km/hr
s1/s2=underroot(t2/t1)
s1/s2=underroot(4/9)
s1/s2=2/3
in question value of 2 is 36kmph
therefore value of 3 i.e s2 will be 54kmph
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67 / 146
Five different roads join a village to nearby city. The no. of different ways in which a person can go to town and come back is ?
A25 ways
B35 ways
C22 ways
D45 ways
Answer: Option A
Explanation:If we choose 1st road, To come back we have 5 ways..
similarly for 2nd,3rd,4th,5th road.
so total ways = 5+5+5+5+5 = 25 ways
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68 / 146
Which of the following values of 'n' satisfies the in-equality n2 - 24n + 143 < 0?
An < 11
Bn > 13
C11 < n < 13
D11 > n > 13
ENone of these
Answer: Option C
Explanation:n^2 - 24n + 143 < 0
=> (n-11)(n-13) < 0
=> 11 < n < 13
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69 / 146
A car starts from rest and accelerates uniform upto speed 90 km/hrs in 5 sec. Total distance covered by car in this time will be
A62.5 m
B60 m
C54.5 m
DNone of these
Answer: Option A
Explanation:Speed of car at last instant of given interval
= 90*5/ 18 m/s = 25 m/s
so average speed = 0+25 / 2
Therefore distance = 5 * 25/2 = 125/2 = 62.5 m
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70 / 146
In a bid two firms A and B competing against each other.If the probability of bid amount quoted by B being lower than that of A is 0.8 and if it is known that the bid is won by the ones who quotes the lowest price,what is the probability that A wins the bid?
A0.8
B0.004
C0.2
D0.001
Answer: Option C
Explanation:Probability of 'a' biding lower than 'b' = 1 - 0.8 = 0.2
so probability of wining of 'a' = 0.2
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