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# Placement Questions & Answers :: TCS

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671. If 43 times of two digit numbers is 34 times of two digit reverse no . and sum of number is 14 then what is the number?

Explanation:

43 time the no. And 34 time the reverse no.
43(10x+ y)=34(10y+ x)
430x+ 43y= 340y+34x
430x+43y-340y-34x=0
To solve this equation become
4x-3y=0 -------------- (1)

Sum of no. And reverse no. Is 14
X+ Y= 14 ------------- (2)
To solve both equation value of x and y
X= 6 and y= 8
So, number will be 68