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What is the minimum value of abs(187m - 396n - 526) as m, n take all integer values? Here abs is the absolute value function (that is, if x > 0, then abs(x) = x and if x < 0, then abs(x) = - x).
A0
B9
C2
D1
Answer: Option C
Explanation:187m-396n-526=187(m-2n-3)-22n+35
consider
m-2n-3=1
187(1)-22n+35=222-22n
the value =2 when n=10
m-2n-3=1
n=10
m=24
m,n are integers
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A conical tent is to accommodate 10 persons. Each person must have 6 sq.meter space to sit and 30 cubic meter of air to breathe. What will be the height of the cone?
A150m
B37.5 m
C15 m
D75 m
Answer: Option C
Explanation:Amount of area reqd. by 1 person to stand = 6 sq.metre
Amount of area reqd. by 10 person to stand = 6x10 sq.metre i.e 60 sq.metre
So,
Base Area, pi*r*r=60
=>r*r = 60/pi ---------------(1)
Now,
Volume of air reqd. to breathe 1 person= 60 cu.metre
Volume of air reqd. by 10 person to breathe = 60x10=600 cu.metre
So,
Volume, 1/3*pi*r*r*h = 300 ---------------------(2)
Putting the value of eqn 1 in eqn 2, we get
1/3*pi*60/pi*h = 300
=> 1/3*60*h = 300
=> 20*h = 300
=> h = 300/20 = 15
Therefore height = 15 metres
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How many prime numbers are there which are less than 100 and greater than 3 such that they are of the following forms 4x + 15y - 1
A11
B12
C2
D7
Answer: Option C
Explanation:Let the number be N.
So N = 4x + 1 = 5y - 1
=> x=5y?24
y = 2 satisfies the equation. So minimum number satisfies both the equations is 9 and general format of the numbers which satisfies the equation = k. LCM (4, 5) + 9 = 20k + 9.
Now by putting values 1, 2, 3 . . . . for k, we get 29, 49, 69, 89. Of which only 29, 89 are primes.
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In this problem, ABS(x) provides absolute value of x, without regard to its sign. For example ABS(3) = ABS(-3) = 3
The graphs of y = – ABS(x – a) + b and y = – ABS(x – c) + d intersect at points (2,5) and (8, 3).
Find a + c
A8
B10
C7
D5
Answer: Option A
Explanation:Both curves intersect at (2, 5)
So 5 = – |2 – a| + b ? 5 + |2 – a| – b = 0 - - - (1)
5 = – |2 – c| + d ? 5 + |2 – c| – d = 0 - - - (2)
Also,
3 = – |8 – a| + b ? 3 + |8 – a| – b = 0 - - - (4)
3 = – |8 – c| + d ? 3 + |8 – c| – d = 0- - - (4)
Equating 1 and 3, 5 + |2 – a| = 3 + |8 – a| ? 2 + |2 – a| = |8– a|
So a = 4
Similarly if we equate 2 and 4, we get c = 4
a + c = 8
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There are ten points marked on a straight line, and another 11 points marked on a line parallel to this one. How many triangles could be formed using these points ?
A495
B550
C1045
D2475
Answer: Option C
Explanation:10C2 * 11C1 + 10C1 * 11C2
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There are three boxes containing red, white and mixed balls, which are mislabelled. It is known that one of the boxes contains only white and one only red balls. The third contains a mixture of red and white balls. You are requested to correctly label the boxes with the labels Red, White and Red & White, by picking a sample of one ball from only one box. What is the label on the box you should sample ?
AWhite
BRed
CRed & White
DNot possible to determine from a sample of one ball
Answer: Option D
Explanation:With the given information, it is not possible to decide which sample should be chosen.
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40% of the employees of an organization are men, of these 75% are earning more than Rs. 25,000/- per year. If 45% of the total employees of the company earn more than Rs. 25,000/- per year, then find the fraction of women who earn less than Rs. 25,000/- per year.
A2/11
B1/4
C1/3
D3/4
Answer: Option D
Explanation:Let 100 be the total strength Þ 40 M, 60 W,
30 M (>25000), overall 45 (>25000) Þ 15W must be > 25000
Þ 15/60 = 1/4.
Hence Ans. 1 - 1/4 = 3/4
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A square field of side 500 m each is surrounded by a compound wall. A fence is to made such that it encloses a triangle formed by two compound walls and the fence. If the length of the fence is 100m then the maximum possible area in square metres of the triangle can be :
A2500
B10000
C5000
D20000
Answer: Option A
Explanation:The triangle has to be max area and hence should be equilateral but cannot be as the angle in the sq shall be 90 degrees. Hence the triangle is isosceles with the angles as 90, 45, 45. Hence the other two sides shall be 50Ö 2 each. So area is 0.5 x base x ht etc. etc.
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Given n^2 = 123456787654321, find n.
A12345678
B11111111
C1234578
D1111111
Answer: Option B
Explanation:Here is no explanation for this answer
ShortCut By :: VIKAS KUMAR SINGHSolution: This question needs to be remembered as there is no appropriate way to solve it.
11111111^2=123456787654321
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The remainder when (7)84 is divided by 342 is :
A0
B1
C49
D341
Answer: Option B
Explanation:784 = (343) 28
Now (343) º 1mod (342) Þ (343)28 = 128 mod (342) = 1mod (342).
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Here is the list of questions asked in TCS Aptitude Test Question with Answers page 37. Practice TCS Written Test Papers with Solutions and take Q4Interview TCS Online Test Questions to crack TCS written round test. Overall the level of the TCS Online Assessment Test is moderate. Only those candidates who clear the written exam will qualify for the next round, so practic all the questions here and take all the free tests before going for final selection process of TCS
