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341 / 652
Apples cost L rupees per kilogram for the first 30 kilograms and Q per kilogram for each additional kilogram. If the price paid for 33 kilograms of Apples is Rs.1167 and for 36 kilograms of apples if Rs.1284, then the cost of the first 10 kgs of apples is:
ARs.117
BRs.350
CRs.281
DRs.1053
Answer: Option B
Explanation:By question
30L + 3Q = 1167 ------ (1)
30L + 6Q = 1284 -------(2)
By solving eq. (1) & (2)
Q = 39, L = 35
So, cost of first 10 kgs of apples = 35 * 10 = Rs. 350
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342 / 652
A and B can do a piece of work in 40 days. Thier skills of doing the work are in the ratio 8:5. how many days will A take to engage alone ?
A65 days
B66 days
C55 days
DNone of these
Answer: Option A
Explanation:Ratio of efficiency of A:B=8:5
Total Efficiency=13
They complete the work in 40 days
When the efficiency of A is 8
A could complete the work in (40/8)*13=65 days
Thus. A alone can do the work in 65 days
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343 / 652
A number increased 37 1/2% gives 33. So, the number is
A16
B22
C24
D43
Answer: Option C
Explanation:Let x be that number
x+(37 1/2 % of x)=33
x+3x/8=33
11x=33*8
x=33*8/11=24
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344 / 652
Smallest no which when multiplied by 12748 gives a perfect square is
A3187
B3183
C3245
D4532
Answer: Option A
Explanation:Here is no explanation for this answer
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345 / 652
what is the unit digit of(2^3)^123456
A2
B4
C8
D6
Answer: Option D
Explanation:(2^3)^123456=2^370368
Take unit position of power
2^8=256
so unit position is 6
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346 / 652
Jake and paul start together to walk 10kms jake walks 1.5kmph faster than paul and arrives at his destination 1.5 hours earlier than paul jakes speed walking is
A6kmph
B2kmph
C4 kmph
D8 kmph
Answer: Option C
Explanation:Let speed of jake = x kmph.
So, speed of paul = ( x - 1.5 ) kmph.
Time difference =1.5hours
Total Distance = 10km
10/(x-1.5) -10/x = 1.5
By solving the above eq.
x = 4 kmph
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347 / 652
Find the number of zeros in the expression 15*32*25*22*40*75*98*112*125.
A9
B7
C14
D12
Answer: Option A
Explanation:Expen 15*32*25*22*40*75*98*112*125 as below
(3*5)*(2^5)*(5^2)*(11*2)*(5*2^3)*(3*5^2)*(49*2)*(7*2^4)*(5^3)
Total no. of 5 = 9 & n.o of 2=14
So, Total number of zero = 9
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348 / 652
If a^x= b , b^y= c and c^z = a , then what is the value of x*y*z ?
A1
B3
C2
DCannot be determined
Answer: Option A
Explanation:((((a)^x)^y)^z)=a
so.(a)^xyz=a
so xyz=1
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349 / 652
In how many ways a team of 11 must be selected a team 5 men and 11 women such that the team must comprise of not more than 3 men.
A1565
B2256
C2456
D1243
Answer: Option B
Explanation:Here is no explanation for this answer
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350 / 652
How many liters of a 90% of concentrated acid needs to be mixed with a 75% solution of concentrated acid to get a 30 liter solution of 78% concentrated acid?
A3
B4
C6
D10
Answer: Option C
Explanation:concentration is given which is wrt 100, hence we can take x lt of 90% and (30-x)of 75%
x*90 + (30-x)*75 = 30*78 hence the ans is 6 ltr.
90 75
\ /
78 78-75:90-78=>3:12=>1:3
/ \
3 12 the ratio becomes 1:4 he has given mixture contains 30l so according to ratios 5parts -30l
1part =6l
the ratio is 1:4 so 6L of 90%concertaed acid is mixed with 24 l of 75%concentrated acid so ans is 6l
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