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71 / 483
Train A starts from Meerut at 12:00 pm & reach at Delhi on 2:30 pm & train B starts from Delhi at 12:15pm and reach at Meerut on 2:15pm. So, when both trains crosses each other ?
A2:00 PM
B1.30 pm
C1.15 pm
D1:00 PM
Answer: Option C
Explanation:Lets assume Distance between Meerut & Delhi = x kms
Trains meet t hours after 12.15pm
Speed of A= x/150 kms/min.
speed of B = x/120 kms/min.
Distance covered by A in (t+15) min + Distance covered by B in y hours
=x (x/150)* (y+15) + (x/120) * y = x
=> 1/150 * (y+150) + 1/120 *y = 1
=> y/150 + 1/10 + y/120 = 1
=> Y=60
trains meet at (12.15 + 60) = 1:15 PM
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72 / 483
one man can do a piece of work in 10days. one boys join him & he complete the work in 6days . if he gets 50rs for his work then what will be the share of the boy.
ARs. 40
BRs. 20
CRs. 24
DRs. 30
Answer: Option B
Explanation:man can do work in 10 days
man + boy can do a work in =6 days
so work done by man in 1 day is 6
and work done by boy in 1 day is 4.
so share of boy will be (4/10) * 50= 20 Rs.
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73 / 483
A square and an equilateral triangle have the same perimeter. What is the ratio of the area of the circle circumscribing the square to the area of the circle inscribed in the triangle?
A9:32
B8:27
C32:09:00
D27:08:00
Answer: Option D
Explanation:let x be side of square
perimeter of square=4x=perimeter of triangle=3*side of triangle
so side of eq. triangle=(4/3)*x
diameter of circle circumscribing the square=sqrt(2)*x
area of circle circumscribing the square=pi*(sqrt(2)*x)^2/4=(pi/2)*x^2 ----(1)
to find radius of the circle inscribed in the triangle
area of triangle=r*s=sqrt(3)/4 * (4x/3)^2
now s=(4/3)*x+(4/3)*x+(4/3)*x/2=2x
so sqrt(3)/4 * (4x/3)^2=r*2x gives
r={2/3*(3^1/2)}*x
area of the circle inscribed in the triangle=pi*({2/3*(3^1/2)}*x)^2
=pi*(4/27)*x^2 -------(2)
so reqd ratio= eqn(1)/eqn(2)
=((pi/2)*x^2)/(pi*(4/27)*x^2)=27/8
so reqd ratio=27:8
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74 / 483
Two trains for Palwal leave Kanpur at 10 a.m and 10:30 am and travel at the speeds of 60 Kmph and 75 Kmph respectively. After how many kilometers from Kanpur will the two trains be together?
A250 km
B150 km
C100 km
D200 km
Answer: Option B
Explanation:Lets assume two train meet at X km distance from kanpur.
Given First train speed 60 kmph, second train speed 75 kmph
Second train start after 1/2 hrs.
Time taken by first train to cover X km = x/60 h
Time taken by 2nd train to cover X km=x/75 h
Now, x/60 - x/75=1/2
so x=150.
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75 / 483
5 tables and 10 chairs were sold for 20000.15%gain for table,10%loss on chair.overall profit Rs 750.the CP of table is
ARs. 2140
BRs. 2240
CRs. 3000
DRs. 2500
Answer: Option A
Explanation:Lets assume cost of table is X and cost of chair is Y.
sold price is 20000 and profit is 750 .
so cost for both is 19250.
=> 5X+10Y=19250 ------------ (1)
=> 5*(115/100)X + 10* (90/100)Y =20000 ------- (2)
By solving both eq.
We get X=2140
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76 / 483
An elephant fell into a wall of depth 20mts.Everyday it climbs 4mts but at the end falls by 2mts.Find the number of days it would take for the elephant to get out of the wall
A10 days
B7 days
C9 days
D8 days
Answer: Option C
Explanation:Here is no explanation for this answer
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77 / 483
A quantity of tea is sold at Rs. 5.75 per kilogram. The total gain by selling the tea at this rate is Rs. 60. Find the quantity of tea being sold if a profit of 15% is made on the deal.
A90 kg
B60 kg
C80 kg
D70 kg
Answer: Option C
Explanation:Here is no explanation for this answer
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78 / 483
Anirudh, Harish and Sahil invested a total of Rs.1,35,000 in the ratio 5:6:4 Anirudh invested has capital for 8 months. Harish invested for 6 months and Sahil invested for 4 months. If they earn a profit of Rs.75,900,then what is the share of Sahil in the profit?
ARs. 12400
BRs. 14700
CRs.13200
DRs. 15800
Answer: Option C
Explanation:Anirudh invest for 8 months,haris invested for 6 and
sahil for 4 months in the ratio of 5:6:4
so ratio = 5*8 : 6*6 : 4*4
=> 40:36:16
=> 10:9:4
So sahil's profit=(4/23)*75900 = 13200
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79 / 483
A task can be completed by D and E with in 12 days if they worked together. E and F however can complete with in period of 20 days. If three of them agree to work together then how many days will be required to complete the task ?
A20
B40
C50
DNone of these
Answer: Option D
Explanation:D and E can complete within 12 days and when F is also ready to work with D and E obviously time required would be less than 12 days.
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80 / 483
Two trains whose respective lengths are 240 m and 360 m cross each other in 30 seconds when they are moving in opposite directions and in 1 minute 40 seconds when they are moving in the same direction. What is the speed of the faster train (kmph) ?
A46
B11 1/2
C46.8
D30
Answer: Option C
Explanation:Lets assume Trains speed are S1 m/sec and S2 m/sec respectively.
In opposite Direction
------------------------
Then 30 = (240 + 360)/(S1+S2).
=> S1 + S2 = 20 ------------(1)
In same Direction:
their relative speed = (S1-S2) {S1>S1}
so (S1-S2) = 600/100
=> S1-S2=6.------(2)
By solving the both eq. (1) (2) we get,
S1=13 and S2=7
So faster train speed = 13 * (18/5) km/hr. = 46.8 km/hr.
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