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611 / 652
If two three and four cuts are made parallel to different faces of a cube, then what is the number of identical pieces obtained?
A55
B60
C20
D12
Answer: Option B
Explanation:Each time one more piece is added (if two cuts will be made then there will be basicallu 3 cubes obtained)
so, (2+1)*(3+1)*(4+1) = 3*4*5 = 60
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612 / 652
Mr. D spent Rs.710 in buying 40 copies of three different magazines for his colony club- business india ,business today,business worldpriced at Rs. 12, Rs. 25 and Rs. 15 if the number of copies of business world he bought is heighest among three magazines. What is the number of copies of business india and business world together he must have purchased ?
A36
B26
C28
D30
Answer: Option B
Explanation:Lets assume club-business India as x, business today as y and business world as z.
x+y+z = 40 .....(1)
12x+25y+15z = 710 ..... (2)
From above eq. (1) & (2)
3x-10y = -110
As, 10y and -110 are multiples of 10.
so, x should be a multiple of 10
so, if x=10,y=14,z=16
if x=20,y=17,z=3
As copies of z are more
so, x=10,y=14,z=16
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613 / 652
If A = 2/3(B-C) and C = 1/2(A+B) and A+B+C = 3000, then find C ?
A100
B1000
C999
DNone of these
Answer: Option B
Explanation:A+B+C=3000
So, (A+B) = 3000-C
C=1/2(A+B)
C=1/2(3000-C)
Solving the above equation.
3C=3000
C = 1000
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614 / 652
Thangam and Pandiyamma go for an interview for two vacancies. The probability for the selection of Thangam is 1/3 and whereas the probability for the selection of Pandiyamma is 1/5. What is the probability that none of them are selected?
A3/5
B7/12
C8/15
D1/5
Answer: Option C
Explanation:Probability of thangam being selected = 1/3
Probability of thangam not being selected = (1-1/3) = 2/3
Probability of pandiyamma being selected = 1/5
Probability of pandiyamma not being selected = (1-1/5) = 4/5
Probability that both are not selected = 2/3 * 4/5 = 8/15
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615 / 652
Find the greatest number that will divide 148 246 and 623 leaving remainders 4 6 and 11 respectively.
A11
B15
C12
D45
Answer: Option C
Explanation:Difference of the dividend and remainder gives you the divisible number
So, Hcf of ((148-4),(246-6),(623-11)
144=12*12
240=12*20
623=12*51
So, the HCF is 12.
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616 / 652
What is the maximum value of n such that 146! is perfect divisible by 5n ?
A12
B32
C35
D43
Answer: Option C
Explanation:= [146/5] + [146/52] + [146/53];
= 29+5+1.
= 35.
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617 / 652
There is a 3*3 matrix . you have 2 colors red and blue. In how many ways you can fill the colors in the boxes so that if u rotate the matrix by 180 degree we get the same matrix ?
A31 ways
B32 ways
C41 ways
DNone of these
Answer: Option B
Explanation:for 3*3 matrix if we rotate 180 degrees , there are 32 ways
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618 / 652
What will be the reminder when (1234567890123456789)^24 is divided by 6561 ?
A3
B4
C1
D0
E5
Answer: Option D
Explanation:The digital sum of number is
(1+2+3+4+5+6+7+8+9+0+1+2+3+4+5+6+7+8+9)=90=(9+0) = 9
So it is divisible by 3 or 9
The given divisor 6561 = 9^4
So, 9^24/9^4 Reminder is 0
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619 / 652
Which is true about fputs returns?
AEOF if an error occurs
BNon-negative if no error
CBoth (A) & (B)
DNone of the mentioned
Answer: Option C
Explanation:Here is no explanation for this answer
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620 / 652
#include
int main()
{
short int i;
scanf("%hd", &i);
printf("%hd", i); return 0;
}
ACompilation error
BUndefined behavior
CWhatever user types
DNone of these
Answer: Option C
Explanation:Here is no explanation for this answer
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Here is the list of questions asked in TCS Aptitude Test Question with Answers page 62. Practice TCS Written Test Papers with Solutions and take Q4Interview TCS Online Test Questions to crack TCS written round test. Overall the level of the TCS Online Assessment Test is moderate. Only those candidates who clear the written exam will qualify for the next round, so practic all the questions here and take all the free tests before going for final selection process of TCS
