Capgemini Placement Papers with Answers
31 / 483
Statement: "If you trouble me, I will slap you." - A mother warns her child.
Assumptions:
I. With the warning, the child may stop troubling her.
II. All children are basically naughty.
AOnly assumption I is implicit
BOnly assumption II is implicit
CEither I or II is implicit
DNeither I nor II is implicit
EBoth I and II are implicit
Answer: Option A
Explanation:The mother warns her child with the expectation that he would stop troubling her. So, I is implicit. The general nature of children cannot be derived from the statement. So, II is not implicit.
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32 / 483
On 8th Dec, 2007 Saturday falls. What day of the week was it on 8th Dec, 2006?
ASaturday
BFriday
CMonday
DTuesday
Answer: Option B
Explanation:The year 2006 is an ordinary year. So, it has 1 odd day.
So, the day on 8th Dec, 2007 will be 1 day beyond the day on 8th Dec, 2006.
But, 8th Dec, 2007 is Saturday
S0, 8th Dec, 2006 is Friday.
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33 / 483
A man owns 2/3 of the market research beauro business and sells 3/4 of his shares for Rs. 75000. What is the value of Business.
A15000
B140000
C150000
D100000
Answer: Option C
Explanation:3/4 of his share = 75000
so his share = 100000.
2/3 of business value = 100000
so total value = 150000
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34 / 483
A computer printer produced 176,400 lines in a given day. If the printer was in operation for seven hours during the day, how many lines did it print per minute?
A125
B122
C123.5
D122.5
Answer: Option D
Explanation:For 24hrs, 176400
For one hr,176400/24=7350 lines
For 7 hrs,7350*7=51450
for one min,51450/(7*60)=122.5
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35 / 483
From its total income, A sales company spent Rs.20,000 for advertising, half of the remainder on commissions and had Rs.6000 left. What was its total income?
A32000
B16000
C36000
D40000
Answer: Option A
Explanation:Let total income is X
X=20,000+(X-20,000/2)+6000
X-X/2=20,000-10,000+6000
X/2=16,000
X=32,000
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36 / 483
On Monday a banker processed a batch of cheques, on Tuesday she processed three times as many, and on Wednesday she processed 4000 cheques. In the three days, she processed 16000 cheques. How many did she process on Tuesday?
A8000
B9000
C10000
D3000
Answer: Option B
Explanation:let monday be m
then tuesday=3m
and they have given wednesday as 4000 cheques
so total three days she processed 16000 cheques i.e
m+3m+4000=16000
4m+4000=16000
4m=12000
m=3000.
so she processed cheques on tuesday=3*3000=9000.
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37 / 483
The cost of four dozen proof machine ribbons and five dozen accounting machine ribbons was Rs.160/-. If one dozen accounting machine ribbons cost Rs.20/-, what is the cost of a dozen proof machine ribbons?
A15
B60
C10
D16
Answer: Option A
Explanation:Lets take proof machine as pm & accounting machine as am.
so, here 4 pm + 5 am=160
given that 1 am=Rs.20 then 5 am=20 x 5=100
substitute this in the above eqn,
now, 4 pm + 100 = 160
4 pm=160 -100
4 pm=60
1 pm=60/4=15
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38 / 483
If a clerk can process 80 cheques in half an hour, how many cheques can she process in a seven and one half hour day?
A800
B1100
C1200
D750
Answer: Option C
Explanation:80 cheques in 1/2 hrs
So in 7.5 hrs she can process,
7.5*80/(1/2) = 1200
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39 / 483
A milk vendor has 2 cans of milk. The first contains 25% water and the rest milk. The second contains 50% water. How much milk should he mix from each of the containers so as to get 12 litres of milk such that the ratio of water to milk is 3 : 5?
A6 litres
B1 litres
C8 litres
D7 litres
Answer: Option A
Explanation:Milk in 1 litre mixture in 1st can = 3/4 litre.
Milk in 1 litre mixture in 2n d can = 1/2 litre.
Milk in 1 litre final mixture = 5/8 litre.
By rule of alligation we have required ratio 5 : 8
3/4 1/2
\ /
(5/8)
/ \
1/8 : 1/8
Therefore ratio of two mixtures =1/8:1/8=1:1
So, quantity of mixture taken from each can =(1/2)*12= 6 litres
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40 / 483
The average length of three tapes is 6800 feet. None of the tapes is less than 6400 feet. What is the greatest possible length of one of the other tapes?
A7600
B7500
C7000
D8000
Answer: Option A
Explanation:Minimum length = 6400
2 tap can be of length 6400,
So the next one will be max = (6800*3)-(2*6400)=7600
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