TCS aptitude test questions and answers
321 / 652
In the below table, If the sum of the numbers in each row column, diagonal are same.
What is the value of (Y+Z)?
A66
B44
C45
DNone of these
Answer: Option A
Explanation:v-2+5=v-16+w
w=19
w+x+5=-16+x+z
19+5=-16+z
z=40
5+z-9=19+y-9
5+40-9=19+y-9
y=26
So, y+z=40+26
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322 / 652
The average marks of 3 students A, B and C is 60. When another student D joins the group, the new average becomes 56 marks. If another student E, who has 3 marks more than D, joins the group, the average of the 4 students B, C, D and E becomes 55 marks. How many marks did A get in the exam?
A50
B54
C51
D53
Answer: Option C
Explanation:Given that A + B + C = 60 * 3 = 180
A + B + C + D = 56 * 4 = 224
Therefore, D = 44
E = 44 + 3 = 47
Given, B + C + D + E = 55 * 4 = 220
B + C + 44 + 47 = 220
? B + C = 220 - 91 = 129
So A + 129 = 180 ? A = 51
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323 / 652
According to the stock policy of a company, each employee in the technical division is given 15 shares of the company and each employee in the recruitment division is given 10 shares. Employees belonging to both committees get 25 shares each. There are 20 employees in the company, and each one belongs to at least one division. The cost of each share is $10. If the technical division has 15 employees and the recruitment division has 10 employees, then what is the total cost of the shares given by the company?
A2650
B3180
C3250
D3120
Answer: Option C
Explanation:Here is no explanation for this answer
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324 / 652
A play school has chocolates which can supply 50 students for 30 days. For the first ten days only 20 students were present. How many more students can be accommodated into the earlier group such that the entire chocolates get consumed in 30 days. Assume each student takes the same number of chocolates.
A45
B60
C55
D70
Answer: Option A
Explanation:Let each students gets 1 chocolate.
Total chocolates = 50 * 30 = 1500
If first 10 days only 20 students were present, then total chocolates consumed = 10 * 20 = 200
Now we are left with 1500 - 200 = 1300 chololates. These were to be consumed in 20 days.
So each day 1300/20 = 65 chocolates were to be distributed.
So we can add 65 - 20 = 45 students.
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325 / 652
A number plate can be formed with two alphabets followed by two digits, with no repetition. Then how many possible combinations can we get?
A58500
B67600
C65000
D64320
Answer: Option A
Explanation:26 * 25 * 10 * 9 = 58500
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326 / 652
Three containers A, B and C are having mixtures of milk and water in the ratio of 1:5, 3:5, 5:7 respectively. If the capacities of the containers are in the ratio 5:4:5, find the ratio of milk to water, if all the three containers are mixed together.
A53:115
B53:113
C54:115
D54:113
Answer: Option A
Explanation:Assume that there are 500,400 and 500 litres respectively in the 3 containers.
Then, we have, 83.33, 150 and 208.33 litres of milk in each of the three containers.
Thus, the total milk is 441.66 litres. Hence, the amount of water in the mixture is
1400 - 441.66 = 958.33liters.
Hence, the ratio of milk to water is
441.66 : 958.33 => 53:115 (using division by .3333)
The calculation thought process should be
(441*2+2) : (958*3+1) = 1325 : 2875.
Dividing by 25 => 53:115.
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327 / 652
All even numbers from 2 to 98 inclusive, except those ending 0, are multiplied together. What is the rightmost digit (the units digit) of the product?
A6
B2
C0
D4
Answer: Option A
Explanation:2^10 * 4^10 * 6^10*8^10 = 2^70 * 3^10
2^2 * 3^2 = 36
So, the right most digit = 6
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328 / 652
X takes 4 days to complete one-third of a job,Y takes 3 days to complete one-sixth of the same work and Z takes 5 days to complete half the job.If all of them work together for 3 days and X and Z quit, how long will it take for Y to complete the remaining work done.
A6 days
B7 days
C5.1 days
D8.1 days
Answer: Option C
Explanation:X completes 1/3rd in 4 days = 33.33 % job in 4 days.
X One day work = 8.33%
Y one day work = 5.55% [As he complete 1/6 job = 16.66 % job in 3 days]
Z one day work = 10%
Work done in 3 days by X, Y and Z
= 25 + 16.66 + 30 = 71.66 %
Remaining work will be done by Y in,
28.33/5.55 = 5.1 days.
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329 / 652
Four people each roll a fair dice once. Find the probability that at least two people will roll the same number?
A5/18
B13/18
C1295/1296
DNone of these
Answer: Option B
Explanation:The number of ways of rolling a dice where no two numbers probability that no one rolls the same number = 6*5*4*3
Now total possibilities of rolling a dice = 64
The probability that a no one gets the same number = 6*5*4*3/64=5/18
So the probability that at least two people gets same number = 1?5/18=13/18
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330 / 652
A certain sum of money is sufficient to pay either George's wages for 15 days or Mark's wages for 10 days. For how long will it suffice if both George and Mark work together?
A8 days
B6 days
C9 days
D5 days
Answer: Option B
Explanation:Let the money to be paid = 30 rupees.
So, George daily wage = 30/15 = 2
and Mark daily wage = 30/10 = 3.
If both are working,
then 5 rupees to be paid.
So given sum is sufficient for 30 / 5 = 6 days.
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