[Updated] Goldman Sachs Aptitude Test Questions and Answers
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TCS aptitude questions

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Choose the correct option.

A number when divided by D leaves a remainder of 8 and when divided by 3D leaves a remainder of 21. What is the remainder left, when twice the number is divided by 3D?


A13

B3

C42

DCannot be determined

Answer: Option B

Explanation:

Let's number is N
so N = DX + 8 -------(1)
N = 3DY + 21 ---------(2)

From Eq. 1 & 2
=> D(X-3Y) = 13
"13" is prime number, and its factors will be 1 and 13 only
=> X-3Y must be 1
Let X = 4 and Y = 1, D=13
So, N = 60
Remainder Left = 2N / 3D
= 120 / 39 = 3

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The owner of a boutique decides to calculate the percentage of customers who purchase hats. If 40 percent of the store's customers decide to purchase items, and of those customers 15 percent purchase hats, what percent of the store's customers purchase hats?


A4

B6

C15

D12

Answer: Option B

Explanation:

Suppose there are 100 customers.
Given 40 persons want to purchase items.
15% purchase hats
=> 0.15*40
=> 6 persons want to purchase hats.

=> 6% want to purchase hats.

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SHSTTON
4
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5
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The perimeter of a equilateral triangle and regular hexagon are equal. Find out the ratio of their areas?


A3:2

B2:3

C1:6

D6:1

Answer: Option B

Explanation:

Given, perimeter of a equilateral triangle and regular hexagon are equal
6r=3a
=> a/r = 2
So Ratio of their areas = (sqrt(3)/4)a^2 : 3sqrt(3)/2 r^2
=> a^2/r^2 : 3*2
=> 4:6 => 2:3

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A sealed envelope contains a card with a single digit written on it. Three of the following statements are true and one is false.
I. The digit is 1.
II. The digit is not 2.
III. The digit is not 9.
IV. The digit is 8.
Which one of the following must necessarily be correct?


AII is false

BIII is true

CIV is false

DI is true

 View Answer |  Submit Your Solution | Topic: Uncategorized| Asked In TCS |

Answer: Option B

Explanation:

Three of the given statements are true.
So both II and III are correct, and the given number is one of 1 or 8.
So option b is correct.

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12
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There are 16 teams divided in 4 groups. Every team from each group will play with each other once. The top 2 teams will go to the next round and so on the top two teams will play the final match. Minimum how many matches will be played in that tournament?


A43

B40

C14

D50

Answer: Option A

Explanation:

Here is no explanation for this answer

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SHSTTON
9
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The shopkeeper charged 12 rupees for a bunch of chocolate. but i bargained to shopkeeper and got two extra ones, and that made them cost one rupee for dozen less then first asking price. How many chocolates I received in 12 rupees ?


A10

B16

C14

D18

Answer: Option B

Explanation:

n chocolates = Rs 12
Price per dozen = 144/n
I got n+2 in rs 12 = > Price per dozen = 144/n+2
144/n+2 = 144/n - 1
=> n = 16

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NA
SHSTTON
8
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A number is 101102103104...150. As 101 102 103 103.... 150. What is reminder when divided by 3?


A0

B1

C4

D2

Answer: Option D

Explanation:

Divisibility rule for 3 are like if sum of the digits divisible by 3.
Aum of the digits = 380
Remainder = 380/3 = 2.

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There are two bags containing white and black balls. In the first bag there are 8 white and 6 black balls and in the second bag, there are 4 white and 7 black balls. One ball is drawn at random from any of these two bags. Find the probability of this ball being black.


A21/154

B7/54

C21/77

D41/77

Answer: Option D

Explanation:

Here is no explanation for this answer

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In the below table, the sum of numbers in each column, each row and the two diagonals are the same.

What is the value of (A*B)+(c*d) - (E*F)?


TCS-Mock-Test-The-sum-of-numbers-each-column

A11397

B10333

C10397

DNone of these

 View Answer |  Submit Your Solution | Topic: Uncategorized| Asked In TCS |

Answer: Option C

Explanation:

Here is no explanation for this answer

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8
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Oranges can be packed in sets of 10 oranges in box type A or 25 oranges in box type B. A carton comprising of 1000 oranges of type a and b is packed. How many different combinations are possible in the number of type A and type B boxes while organizing the oranges?


A21

B20

C19

D18

Answer: Option A

Explanation:

The expression will be 10x+25y=1000
the above exp will be satisfied only with multiples of 2 up to 38.
so no. of combinations are 19.
if oranges are packed in type A boxes only= 1 way
if oranges are packed in type B boxes only= 1 way
so total = 19+1+1=21

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