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261 / 291
If a man ate 100 grapes in 5 days, each day eating 6 more than the previous day, how many grapes did he eat on the first day?
AEight
BFive
CTen
DTwelve
Answer: Option A
Explanation:Here is no explanation for this answer
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262 / 291
Statements:
All the windows are doors.
No door is a wall.
Conclusions:
I. Some windows are walls.
II. No wall is a door.
AOnly conclusion (I) follows.
BOnly conclusion (II) follows.
CEither (I) or (II) follows.
DNeither (I) nor (II) follows .
EBoth (I) and (II) follow.
Answer: Option B
Explanation:Here is no explanation for this answer
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263 / 291
Statements:
Same actors are singers.
All the singers are dancers.
Conclusions:
I. Some actors are dancers.
II. No singer is actor.
AOnly conclusion (I) follows.
BOnly conclusion (II) follows.
CEither (I) or (II) follows.
DNeither (I) nor (II) follows .
EBoth (I) and (II) follow.
Answer: Option A
Explanation:Here is no explanation for this answer
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264 / 291
Statements:
All readers are teachers.
All writers are teachers .
Conclusions:
I. Some teachers are writers.
II. Some writers are readers.
AOnly conclusion (I) follows.
BOnly conclusion (II) follows.
CEither (I) or (II) follows.
DNeither (I) nor (II) follows .
EBoth (I) and (II) follow.
Answer: Option A
Explanation:Here is no explanation for this answer
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265 / 291
Ms. Ganesh Mahal, Coimbatore wanted to present each of its customers with a momento rectangle in size. The momentos were of size 25 x 20 cm. The company requested the carpenter to make it in such a way that both 25 cm sides should have 24 nails each and the shorter sides should have 10 nails each. How many decorative nails the carpenter would have used in each momento?
A64
B56
C68
D60
Answer: Option A
Explanation:To begin with there should be one nail in each of the corners.
There should be 22 nails on each of the two longer sides so that the count comes to 24 nails on each of those sides.
There should be 8 nails on each of the shorter sides so that the count becomes 10 nails on each of the shorter sides.
Total nails = 4 corner nails + 2 x 22 nails (longer sides) + 2 x 8 (shorter sides) = 4 + 44 + 16 = 64 nails.
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266 / 291
In an entrance exam of 200 objective questions, a student can score 1 point for every correct answer, loss 1/4 points for every wrong answer and loss 1/2 point for every unanswered question. If he attempts only 160 questions and he scores 100 points then the number of questions answered by him correctly is:
A132
B139
C126
D128
Answer: Option D
Explanation:Let assume, C be the number of questions answered correctly,
and W is the number of questions answered wrongly,
and U is the number of unanswered questions.
So, Total number of questions = 200 = C + W + U
Given that, he attempts only 160 questions.
i.e., U = (200 - 160) = 40
And then, C + W = 160 ------------ (1)
Total score obtained by him = 100 points
Therefore, C -1/4 W - 1/2 U = 100
Putting U value in above, we get
C - 1/4 W = 120 --------- (2)
Solving (1) and (2), we get C = 128
Hence, the number of correct answers is 128.
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267 / 291
Satish was looking at a new building Kohli Towers constructed having height of 200 m. The angle of elevation of the top of building from a point on ground is 30°. What is the distance of the point from the foot of the building?
A166 m
B254 m
C346 m
D273 m
Answer: Option C
Explanation:Given towers Angle APB = 30°. And AB = 200 m
AB/AP = tan 30° = 1/√3
AP = (AB x √3) m
200√3 m = 200 x 1.73 = 346m
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268 / 291
In a game of Chess, a boy lost 3 rounds less than he won. He can score 4 points for a win and loss 2 points for a loss. How many rounds, in all, have he played if his score is 46?
A17
B37
C46
D27
Answer: Option B
Explanation:Let's assume the number of rounds lost by him = x
So, the number of rounds won by him = x+3.
Total rounds played by him = x + x + 3 = 2x+3.
He scores 4 points for a win and loss 2 points for a loss
and his total score is 46.
Therefore, 4 ( x+3 ) - 2x = 46.
4x + 12 - 2x = 46
2x = 34
x =17
So, Required total number of rounds = 2x + 3 = 37.
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269 / 291
From a railway station, trains leave for every 15 minutes and 25 minutes to city A and city B respectively. First train to city A and city B start at 9 am and 10:15 am respectively. If a man arrives to the station in between 11:25 am and 12:25 pm then the probability of getting train for city A is:
A1/4
B4/7
C3/7
D2/5
Answer: Option B
Explanation:Given man arrived station in between 11.25 am and 12.25 pm.
First train to city A is at 9 am and there is a train for every 15 minutes.
Trains for city A will leave at the following times : 9:00 am, 9:15 am, 9:30 am,.......,11:30 am, 11:45 am, 12:00 pm, 12:15pm, and so on.
Number of trains for city A between 11:25 am and 12:25 pm is 4.
First train to city B is at 10:15 am and there is a train for every 25 minutes.
Trains for city B will leave at the following times: 10:15 am, 10:40 am, 11:05 am, 11:30 am, 11:55 am, 12:20 pm, and so on.
Number of trains for city B between 11:25 am and 12:25 pm is 3.
Probability of getting train for city A between 11:25 am and 12:25 pm = Number trains for city A from 11:25 am to 12:25 pm / Total number of trains for city A and B from 11:25 am to 12:25 pm
= 4/7
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270 / 291
An express A starts at 2:30 pm from Karnal station and travel towards Sirsa station at a speed of 80 km per hour. Another express B starts at 4:30 pm from Karnal to Sirsa at the speed of 100 km per hour. How far away from station Karnal will the two trains meet?
A400 km
B500 km.
C800 km
D600 km.
Answer: Option C
Explanation:Train A starts at 2:30 pm from KARNAL to SIRSA.
Train B starts at 4:30 pm from KARNAL to SIRSA.
Lets assume they meet x hours after 2:30 pm.
So, distance traveled by A in x hours or by B in (x-2) hours.
Given, speed of A = 80 km/hr
Distance traveled by A in x hours at 80km/hr ------------ (1)
and Speed of B = 100 km/hr.
Distance traveled by B in (x-2) hours at 100km/hr = 100(x-2) km ------ (2)
As, trains meet after x hours and i.e distance covered by train A in x hours equals distance covered by train B in (x-2) hours.
From eq. (1) and (2)
80x = (x-2)100
=> 20x = 200
x = 10 hours.
So, hey meet after 10 hours from 2:30 pm.
Hence, required distance = 80x = 80 * 10 = 800 km.
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