Infosys Aptitude Test Papers
11 / 291
How many numbers are divisible by 4 between 1 to 100 ?
A25
B24
C18
D20
Answer: Option B
Explanation:Here is no explanation for this answer
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12 / 291
A person's present age is two-fifth of the age of his mother. After 8 years, he will be one-half of the age of his mother. How old is the mother at present?
A32 years
B46 years
C40 years
D44 years
Answer: Option C
Explanation:Lets assume mother's present age = x years
So, the person's present age = 2/5 x years
As per the question:
=>(2/5 x + 8) = 1/2 (x + 8)
=> 2(2x + 40) = 5(x + 8)
=> x = 40
So Mother present age = 40 years.
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13 / 291
In how much time would the simple interest on a certain sum be 0.125 times the principal at 10% per annum?
A2 3/4 years
B1 1/4 years
C2 1/4 years.
D3 1/4 years.
Answer: Option B
Explanation:Lets assume sum = x.
Then, S.I. = 0.125x = 1/8 *x, GivenR = 10%
Formula: Time = (100 * S.I)/(P * R)
Time = (100 *1/8* x) / (x * 10) = (100 *x)/(x*8*10)
= 5/4 = 1 1/4 years.
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14 / 291
A pupil's marks were wrongly entered as 83 instead of 63. Due to the average marks for the class got increased by half. The number of pupils in the class is:
A40
B73
C12
D23
Answer: Option A
Explanation:Lets assume total pupils in the class = x
As per the question: increased by 1/2.
Total increase in marks = (x * 1/2) = x/2
=> x/2 = (83 - 63)
=> x/2 = 20
=> x = 40
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15 / 291
If Rs 510 be divided among A, B, C in such a way that A gets 2/3 of what B gets and B gets 1/4 of what C gets, then their shares are respectively:
ARs 65, Rs 90, Rs 360
BRs 150, Rs 300, Rs 60
CRs 60, Rs 90, Rs 300
DRs 60, Rs 90, Rs 360
Answer: Option D
Explanation:A per the question:
A = 2/3 B and B = 1/4 C
=> A/B = 2/3 and B/C = 1/4
Or A:B = 2:3 and B:C = 1:4 = 3:12
=> A:B:C = 2:3:12
So, A's share = 510 * 2/17 = Rs 60
B's share = 510 * 3/17 = Rs 90
C's share = 510 * 12/17 = Rs 360.
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16 / 291
There is 60% increase in an amount in 6 years at simple interest. What will be the compound interest of Rs. 12,000 after 3 years at the same rate?
ARs. 3420
BRs. 3120
CRs. 3972
DRs. 3240
Answer: Option C
Explanation:Let P = Rs. 100. Then, S.I. Rs. 60 and T = 6 years.
R = (100 x 60)/(100x6) = 10% p.a.
Now, P = Rs. 12000
T = 3 years and R = 10% p.a.
So, C.I. = Rs.[12000 * [(1 + 10/100)^3- 1]]
= Rs. 12000 * 331/1000 = Rs. 3972
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17 / 291
In an election between two candidates first candidate got 60% of votes polled and second Candidate got 280 votes. The total number of votes polled was?
A600 votes
B700 votes
C750 votes
D650 votes
Answer: Option B
Explanation:Let's assume total polled votes = 100 %,
Given, First person got 60%
So, second person get votes = 40 % (remaining votes)
than 40 % = 280
40% = 40*7 = 280
100% = 100*7 = 700 votes
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18 / 291
Two vessels A and B contain spirit and water mixed in the ratio 5:2 and 7:6 respectively. Find the ratio in which these mixture be mixed to obtain a new mixture in vessel c containing spirit and water in the ratio 8:5?
A7:9
B9:7
C3:8
D8:9
Answer: Option A
Explanation:Let's assume C.P. of spirit = Re. 1 per litre.
Spirit in 1 litre mix. of A = 5/7 litre. So C.P of 1 litre mix in A = Re. 5/7.
Spirit in 1 litre mix. of B = 7/13 litre. So C.P of 1 litre mix in B = Re. 7/13.
Spirit in 1-litre mix. of C = 8/13 litre. So C.P. of 1 litre mix in C = Re. 8/13.
By rule of an allegation, we have required ratio X:Y.
(5/7) (7/13)
\ /
(8/13)
/ \
(1/13) (9/91)
So, required ratio = 1/13 : 9/91 = 7:9.
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19 / 291
On the two sides of a road are two tall buildings exactly opposite to each other. The height of the taller building is 60 m. If the angle of elevation from the top of the smaller building to the top of the taller one is 30° and the angle of depression from top of the taller building to the foot of the smaller one is 30°, then find the height of the smaller building.
A45 m.
B30 m.
C40 m.
D20 m.
Answer: Option C
Explanation:Let AB be the taller building of height 60m and CD be the smaller one of height h m.
tan30= DB/AB = DB/60 = 1/v3
DB = 34.64 m
tan30= AE/CE = AE/DB = 1/v3 = AE/34.64
AE = 60 - h = 20
h = 40 m
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20 / 291
The H.C.F of two numbers is 11 and their L.C.M is 7700. If one of the numbers is 275, then the other is:
A308
B208
C318
D283
Answer: Option A
Explanation:Here is no explanation for this answer
ShortCut By :: rlcm*hcf = product of 2 nos
11*7700=275*?
ans =308
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