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171 / 362
Monika purchased a pressure cooker at 9/10th of its selling price and sold it at 8% more than its selling price. Her gain is :
A20%
B18%
C10%
DNone of these
Answer: Option A
Explanation:Let the S.P. of pressure cooker = Rs. X .
So, C.P of pressure cooker = Rs. 9x/10.
Receipt=108% of Rs. X = Rs 27x/25
Gain=Rs (27x/25*9x/10) = Rs (108x-90x/100) = Rs18x/100
Gain %=( 18x/100*10/9x*100) %=20%
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172 / 362
In seven given numbers,the average of first four numbers is 4 and that of last four numbers is also 4. if the average of these seven numbers is 3, the fourth number is?
A3
B4
C7
D11
Answer: Option D
Explanation:Lets assume 7 numbers as a,b,c,d,e,f,g.
Given Average of first 4 nums are 4.
=> (a+b+c+d)/4=4.
=> a+b+c+d=16 ------------ (1)
Given, Average of last 4 nums are also 4.
=> (d+e+f+g)/4=4.
=> d+e+f+g=16 -------- (2)
Given, Average of 7 nums are 3.
(a+b+c+d+e+f+g)/7=3
=> a+b+c+d+e+f+g=21 ---------- (3)
By eq. (1), (2) and (3)
=> 16+16-d=21 => d=32-21 => d=11.
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173 / 362
After striking the floor , a rubber ball rebounds to 4/5th of the height from which it has fallen. Find the total distance that it travels before coming to rest if it has been gently dropped from a height of 120 m.
A540 m.
B960 m.
C1080 m.
D1020 m.
Answer: Option C
Explanation:It means the ball looses 1/5 of its height i.e 20% from 1 to 4/5 then from 4/5 to (4/5 - (4/5 * 1/5)) = 16/25
So it forms a G.P Series of..Multiplied by 2 because it goes up and comes down
(120 +2*(120* 4/5 + 120*16/25 +120* 64/125 + ...+ till Infinity )
=> 120 + 2*120 * (4/5 )/ (1 - 4/5)
=>120 + 960 =1080m
Total distance travelled will be 1080m
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174 / 362
The minimum number of digits required to form every number which is greater than 900 and less than 9,000 is:-
A39
B72
C49
D81
Answer: Option A
Explanation:We have to find the minimum number of numbers required to form every number from 900 to 9,000.
Unit place of a number from 900 to 9,000 can be formed using 0 to 9 digits. i.e., 10 digits.
10's place of a number from 900 to 9,000 can be formed using 0 to 9 digits. i.e., 10 digits.
100's place of a number from 900 to 9,000 can be formed using 0 to 9 digits. i.e., 10 digits.
1000's place of a number from 900 to 9,000 can be formed using 1 to 9 digits. i.e., 9 digits.
Therefore, total number of numbers required is 10 + 10 + 10 + 9 = 39.
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175 / 362
Three years ago, the average age of A, B and C was 27 years and that of B and C, 5 years ago was 20 years. A's present age is :
A30 years.
B35 years.
C40 years.
D48 years.
Answer: Option C
Explanation:Lets assume present ages of A, B and C as x,y, and z respectively.
Three years ago their ages were x-3,y-3,z-3.
Given:
=> (x-3+y-3+z-3)/3 = 27.
=> x+y+z=90.
and 5 years ago:
Then (x-5+y-5)/2=20.
=> y+z=50.
=> x=90-(y+z).
=> x=90-50 = 40 years.
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176 / 362
A coin will be flipped five times. If the results are either 0, 1, 4, or 5 heads, you will receive Rs.10. If the results are 2 or 3 heads, you will have to pay Rs.5. What is your mathematical expectation?
A0.625 Paisa
B0.725 Paisa
C0.825 Paisa
D0.925 Paisa
Answer: Option C
Explanation:4*10*(1/2)^5+2*(-5)*(1/2)^5
(1/2) is probability of getting no of heads.
Therefore calculating above gives 0.825 paisa.
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177 / 362
Sixteen men complete a work in 24 days while 48 children can do it in 16 days. Twelve men started the work, after 14 days 12 children joined them. In how Many days will all of them together complete the remaining work?
A15 days
B14 days
C10 days
D12 days
Answer: Option D
Explanation:Work complete by 12 men in 14 days = 12*14/(24*16) = 7/16
So, Remaining work = 9/16
Work complete by 12 men & 12 children = (12/(24*16)) + 12/(48*16) = (1/32 + 1/64) = 3/64
No. of days = (work complete by 12 men & 12 children / remaining work).
= (3/64)/(9/16) =
Hence answer = 12 days.
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178 / 362
Two liquids are mixed in the proportion of 3:2 and the mixture is sold at $11 per litre at a 10% profit. If the first liquid costs $2 more per litre than the second, what does it cost per litre?
A$10.30
B$10.80
C$10.40
D$10.20
Answer: Option B
Explanation:Given two liquids proportion as 3:2
from the mixtures:
Suppose second liquid cost = $x, then first liquid = $(x+2)
(x-10)/(10-x-2) = 3/2
2x-20 = 24-3x
5x = 44
x=8.8
so first liquid cost is x+2 = 8.80+2 = $10.80
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179 / 362
In a group of cows and hens, the number of legs are 14 more than twice the number of heads. The number of cows is :
A5
B10
C7
D12
Answer: Option C
Explanation:Lets assume no. of cows = x, and no. of hens = y.
So heads = (x+y)
Legs = (4x+2y)
As per condition:
4x+2y = 2(x+y)+ 14
2x = 14 => x = 7.
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180 / 362
The last day of a century cannot be
AMonday
BWednesday
CTuesday
DFriday
Answer: Option C
Explanation:100 years contain 5 odd days.
Last day of 1st century is Friday.
200 years contain (5 * 2) = 3 odd days.
Last day of 2nd century is Wednesday.
300 years contain (5 * 3) = 15 = 1 odd day.
Last day of 3rd century is Monday.
400 years contain 0 odd day.
Last day of 4th century is Sunday.
This cycle is repeated.
Last day of a century cannot be Tuesday or Thursday or Saturday.
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