Campus placement papers of IBM
161 / 438
On a given day, a bank had 16000 cheques returned by customers. Inspection of the first 800 cheques indicated that 100 of those 800 had errors and were therefore the available immediately for data processing. On this basis, hwo many cheques would be available immediately for data processing on that day?
A14000
B13520
C14500
DNone
Answer: Option A
Explanation:It is given for every 800 cheques 100 are error
So (800-100)=700 error free
total 16000 cheques
so dividing them into 800 in each we get (16000/800)=20
so 20 sets of cheques (each 800) where each set has 700 error free
so 20*700=14000
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162 / 438
In a team of 12 persons, 1/3 are women and 2/3 are men. To obtain a team with 20% women how many men should be hired?
A7
B6
C8
D10
Answer: Option C
Explanation:Women = 12(1/3) = 4
so, men = 12-4 = 8
if team needs 20% of women then men Will be 80%
consider u want to hire "x" men
so, (12+x)(80/100) = 8 + x
so, x= 8
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163 / 438
How many words with or without meaning, can be formed by using all the letters of the word, DELHI using each letter exactly once?
A720
B24
C23
D120
Answer: Option D
Explanation:Here is no explanation for this answer
ShortCut By :: VikashDELHI
All 5 letters are different so Number of words possible are: 5!= 120
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164 / 438
A man sold a book at loss of 10%.Had he sold it for 104rs more, he would have earned a profit of 10% .find the cost price of the book
ARs. 400
BRs. 520
CRs. 640
DRs. 840
Answer: Option B
Explanation:Given loss=10% profit=10%
Difference of overall profit and loss=10-(-10)=20%
20% of cp =sp
20/100*cp=104
20*cp=104*100
cp=10400/20
=> cp=520
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165 / 438
A Printer prints a 64 pages per Min .If the it printed for 3 hours except 10 Min when there was an paper jam, how many page did it print?
A10880 pages
B880 pages
C10980 pages
DNone of these
Answer: Option A
Explanation:64 pages in 1 min then,
in 60 min*3hr-10min=170min then
170*64=10880 pages
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166 / 438
An internet recently hired 8 new network,in advertisement 20 network already employed.All new network cam from university A.In addition 75%of computer advertisement came from same university A.what fraction of original 20 network advertisement came from same university A?
A\(\frac{13}{20}\)
B\(\frac{11}{20}\)
C13
D11
Answer: Option A
Explanation:8 new n/w,20 is already employed
Total n/w = 20+8 = 28 n/w
so that 75% came from same university then \(28 \times \frac{75}{100} = 21\)
we all know 8 n/w is recently hired then 21-8 = 13
=> the fraction is = \(\frac{13}{20}\)
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167 / 438
A trader allows a discount of 5 percent to his customers. What price should he mark on a article the cost price of which is Rs. 800 so as to make clear profit of 25 percent on his outlay?
ARs.1000
BRs.1053
CRs.1200
DRs.11233
Answer: Option B
Explanation:cp=800 , profit=25%
sp=800 * 125/100=1000
and
sp=marked price * (100-5)/100
1000=marked price * 95/100
marked price = 1052.6 = Rs.1053
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168 / 438
Let X be a four-digit number with exactly three consecutive digits being same and is a multiple of 9. How many such X?s are possible?
A22
B19
C20
D10
Answer: Option C
Explanation:Let the four digit number be ?aaab? or baaa?.
Since, the number has to be a multiple of 9, therefore 3a+b should be either 9, 18 or 27.
Case I: 3a+b=9
Possible cases are: (1116,6111,2223,3222,3330,9000)
Case II: 3a+b=18
Possible cases are: (3339,9333,4446,6444,5553,3555,6660)
Case III: 3a+b=27
Possible cases are: (6669,9666,8883,3888,7776,6777,9990)
Hence, total number of cases is 20.
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169 / 438
In a bank 60 percent employees are men.80%men and 20%women belong to retirement plan. what percent of people belong to retirement plan?
A48%
B56%
C60%
D80%
Answer: Option B
Explanation:60% employees are men => 40% are women.
80% of 60 % men is 48% and 20% of 40% women is 8%.
so total is 48+8=56%.
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170 / 438
A can do a work in 6 days , B can do a work in 8 days and C can do it in 12 days. B left work after 6 days. For how many number of days should A and C should work together to complete the remaining work ?
A1 Day
B2 Days
C1 1/3 Days
DNone of these
Answer: Option A
Explanation:A complete work in 6 days
B complete work in 8days
C complete work in 12 days
B's 1 day work=1/8
6 day's work=6/8
remaining work=1-6/8=2/8=1/4
A+C 1 day work together = 1/6+1/12=1/4
so A and C work 1 day to complete remaining work
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