Campus placement papers of Capgemini
161 / 483
Some quantity of petrol is found to be adulterated to the extent of 15%. What proportion of the adulterated petrol should be replaced with pure petrol to take the purity level to 95%?
A65
B66.67
C67
D76
Answer: Option B
Explanation:Lets assume x ltr pure petrol is added and the volume becomes 100ltr.
So, petrol solution
x+85)/100(100-x)=95 (95 is the purity level in the final solution)
=>x+85-0.85x=95
=>x=66.67
So, 66.67 ltr of pure petrol is added to the adulterated solution.
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162 / 483
In a race from point X to point Y and back, Jack averages 30miles/hr to point Y and 10 miles/hr back to point X. Sandy averages 20 miles/hr in both directions. If Jack and Sandy start race at same time, who will finish first?
ASandy
BJack
CBoth
DNone of these
Answer: Option A
Explanation:Lets assume distance between Point X and Point Y = d
Jack's time = d/30 + d/10 = 4d/30 = 2d/15 = 0.1333d
Sandy's time = d/20 + d/20 = d/10 = 0.1d
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163 / 483
Three wheels make 18, 24, 54 revolutions per minute. Each has a black mark on it. It is aligned at the start. When does it align again for the first time?
A2 Seconds
B10 Seconds
C12 seconds
DNone of these
Answer: Option B
Explanation:Let the time be x minutes.
Therefore 18x 24x 54x
Hcf = 6
Therefore time = 1/6 minute ie 10 secs
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164 / 483
Thomas bought X number of sports goods for Rs.9000. If each item was cheaper by Rs.30 then with the same amount he could have bought 50 more items than X. Find the number of items bought by Thomas ?
A140
B200
C210
D100
ENone of these
Answer: Option D
Explanation:Transaction I
Thomas have bought X items for Rs.9000.
Then the cost of each item = Rs.9000/X ...(1)
Transaction II
If each item was cheaper by Rs.30, he could have bought 50 more items.
Therefore, with Rs.30 discount, the amount of each item = Rs.9000 / X + 50 ...(2)
We know that the cost of each item in transaction II will be lesser than that of transaction I by Rs. 30.
i.e (1) - (2) = 30
Since he bought 50 more items when cost of each item is less by Rs.30 then we have
9000/X - 9000/X + 50 = 30
1/X - 1/X + 50 = 30/9000
50 / X(X + 50) = 1/300
X(X + 50) = 15000
X^2 + 50X = 15000
X^2 + 50X - 15000 = 0
(X+150)(X-100) = 0
X = -150 or X = 100
X cannot be a negative value. Therefore, X = 100.
Hence the answer is 100.
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165 / 483
The straight line 2x + 3y = 12 passes through quadrant ?
A1st
B2nd
C3rd
D4th
Answer: Option A
Explanation:2x/12 + 3y/12=1
x/6 + y/4=1
so (x,y)=(6,4)= 1st quadrant.
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166 / 483
3 cos 80° cosec 10° + 2 cos 59° cosec 31° = ?
A7
B4
C5
DNone of these
Answer: Option C
Explanation:Hint: cosec 8 = 1/sin 8
(3 * cos 80/sin 10) + (2 * cos 59/sin 31)
=> (3 * cos 80/cos 80) + (2 * cos 59/sin 59)
Hint: [ sin(90-x)= cosx ]
=> 3(cos 80/sin(90-80))+2(cos 59/sin(90-59)) = 3+2 = 5
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167 / 483
If m=(2-?3),then the value of (m^6+m^4+m^2+1) /m^3 is:
A64
B56
C69
D52
Answer: Option B
Explanation:After dividing by m^3 ... m^3+m+1/m + 1/m^3 .
Find value of 1/m by rationalizing we get 1/m = 2 + _/3 also find 1/m^3
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168 / 483
The section of a solid right circular cone by a plane containing vertex and perpendicular to base is an equilateral triangle of side 10 cm. find the volume of the cone?
A221.73 cm3
B223.73 cm3
C228.73 cm3
D226.61 cm3
Answer: Option D
Explanation:Volume of the cone = 1/3 (PI*R*R*H)
Since the cone is formed from by an equilateral triangle, all sides are equal that is slope = diameter = 10
So, height = (10^2) - (5^2) = ?75 [by hypotenuse theorem]
=> Height = 8.66
Volume = 1/3(8.66*3.14*25)
=> Volume = 226.61 cm^3
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169 / 483
2 computer each produces 4800 utility bills in a day. First computer bills at a rate of 9600 per hour while other at the rate of 7800 per hour. When first computer finished its run, how many bills did the other computer still have to print?
A200
B1000
C900
D850
Answer: Option C
Explanation:First computer take 30 minit to print 4800 bills than stop working thus second computer will print for 30 minit.
Hence second computer print per minit= 7800/60 = 130 (in one min)
Hence in 30 minit 130*30 = 3900
Remain to print 4800-3900 = 900
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170 / 483
if x-y+z=19,y+z=20,x-z=3
Find the value of x+4y-5z
A13
B-14
C-13
DNone of these
Answer: Option C
Explanation:x-y+z=19 ------ (1)
y+z=20 -------- (2)
x-z=3 -----------(3)
Now substract eq 4 and eq 1
=> z=12.
By, Using z = 12 in eq 2
=> y=8
By, Using z=12 in eq 3
=> x=15
By, Putting values of x, y and z in
x+4y-5z = 15+32-60 = -13
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