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Campus placement papers of Capgemini

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Tot. Mock Test: 19


Total Qs: 483+

NA
SHSTTON
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Choose the correct option.

Some quantity of petrol is found to be adulterated to the extent of 15%. What proportion of the adulterated petrol should be replaced with pure petrol to take the purity level to 95%?


A65

B66.67

C67

D76

Answer: Option B

Explanation:

Lets assume x ltr pure petrol is added and the volume becomes 100ltr.
So, petrol solution
x+85)/100(100-x)=95 (95 is the purity level in the final solution)
=>x+85-0.85x=95
=>x=66.67
So, 66.67 ltr of pure petrol is added to the adulterated solution.

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NA
SHSTTON
18
Solv. Corr.
38
Solv. In. Corr.
56
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162 / 483

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In a race from point X to point Y and back, Jack averages 30miles/hr to point Y and 10 miles/hr back to point X. Sandy averages 20 miles/hr in both directions. If Jack and Sandy start race at same time, who will finish first?


ASandy

BJack

CBoth

DNone of these

Answer: Option A

Explanation:

Lets assume distance between Point X and Point Y = d

Jack's time = d/30 + d/10 = 4d/30 = 2d/15 = 0.1333d
Sandy's time = d/20 + d/20 = d/10 = 0.1d

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NA
SHSTTON
20
Solv. Corr.
77
Solv. In. Corr.
97
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Three wheels make 18, 24, 54 revolutions per minute. Each has a black mark on it. It is aligned at the start. When does it align again for the first time?


A2 Seconds

B10 Seconds

C12 seconds

DNone of these

Answer: Option B

Explanation:

Let the time be x minutes.
Therefore 18x 24x 54x
Hcf = 6
Therefore time = 1/6 minute ie 10 secs

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NA
SHSTTON
2
Solv. Corr.
45
Solv. In. Corr.
47
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Thomas bought X number of sports goods for Rs.9000. If each item was cheaper by Rs.30 then with the same amount he could have bought 50 more items than X. Find the number of items bought by Thomas ?


A140

B200

C210

D100

ENone of these

Answer: Option D

Explanation:

Transaction I

Thomas have bought X items for Rs.9000.
Then the cost of each item = Rs.9000/X ...(1)

Transaction II

If each item was cheaper by Rs.30, he could have bought 50 more items.
Therefore, with Rs.30 discount, the amount of each item = Rs.9000 / X + 50 ...(2)

We know that the cost of each item in transaction II will be lesser than that of transaction I by Rs. 30.

i.e (1) - (2) = 30

Since he bought 50 more items when cost of each item is less by Rs.30 then we have
9000/X - 9000/X + 50 = 30
1/X - 1/X + 50 = 30/9000
50 / X(X + 50) = 1/300
X(X + 50) = 15000
X^2 + 50X = 15000
X^2 + 50X - 15000 = 0
(X+150)(X-100) = 0
X = -150 or X = 100
X cannot be a negative value. Therefore, X = 100.
Hence the answer is 100.

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NA
SHSTTON
23
Solv. Corr.
15
Solv. In. Corr.
38
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The straight line 2x + 3y = 12 passes through quadrant ?


A1st

B2nd

C3rd

D4th

Answer: Option A

Explanation:

2x/12 + 3y/12=1
x/6 + y/4=1

so (x,y)=(6,4)= 1st quadrant.

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NA
SHSTTON
15
Solv. Corr.
13
Solv. In. Corr.
28
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3 cos 80° cosec 10° + 2 cos 59° cosec 31° = ?


A7

B4

C5

DNone of these

 View Answer |  Submit Your Solution | Topic: Uncategorized| Asked In Capgemini |

Answer: Option C

Explanation:

Hint: cosec 8 = 1/sin 8
(3 * cos 80/sin 10) + (2 * cos 59/sin 31)
=> (3 * cos 80/cos 80) + (2 * cos 59/sin 59)
Hint: [ sin(90-x)= cosx ]
=> 3(cos 80/sin(90-80))+2(cos 59/sin(90-59)) = 3+2 = 5

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NA
SHSTTON
11
Solv. Corr.
30
Solv. In. Corr.
41
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If m=(2-?3),then the value of (m^6+m^4+m^2+1) /m^3 is:


A64

B56

C69

D52

Answer: Option B

Explanation:

After dividing by m^3 ... m^3+m+1/m + 1/m^3 .
Find value of 1/m by rationalizing we get 1/m = 2 + _/3 also find 1/m^3

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NA
SHSTTON
7
Solv. Corr.
34
Solv. In. Corr.
41
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The section of a solid right circular cone by a plane containing vertex and perpendicular to base is an equilateral triangle of side 10 cm. find the volume of the cone?


A221.73 cm3

B223.73 cm3

C228.73 cm3

D226.61 cm3

Answer: Option D

Explanation:

Volume of the cone = 1/3 (PI*R*R*H)

Since the cone is formed from by an equilateral triangle, all sides are equal that is slope = diameter = 10

So, height = (10^2) - (5^2) = ?75 [by hypotenuse theorem]
=> Height = 8.66

Volume = 1/3(8.66*3.14*25)

=> Volume = 226.61 cm^3

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NA
SHSTTON
16
Solv. Corr.
16
Solv. In. Corr.
32
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2 computer each produces 4800 utility bills in a day. First computer bills at a rate of 9600 per hour while other at the rate of 7800 per hour. When first computer finished its run, how many bills did the other computer still have to print?


A200

B1000

C900

D850

Answer: Option C

Explanation:

First computer take 30 minit to print 4800 bills than stop working thus second computer will print for 30 minit.
Hence second computer print per minit= 7800/60 = 130 (in one min)
Hence in 30 minit 130*30 = 3900
Remain to print 4800-3900 = 900

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NA
SHSTTON
18
Solv. Corr.
15
Solv. In. Corr.
33
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if x-y+z=19,y+z=20,x-z=3
Find the value of x+4y-5z


A13

B-14

C-13

DNone of these

Answer: Option C

Explanation:

x-y+z=19 ------ (1)
y+z=20 -------- (2)
x-z=3 -----------(3)
Now substract eq 4 and eq 1
=> z=12.

By, Using z = 12 in eq 2
=> y=8
By, Using z=12 in eq 3
=> x=15

By, Putting values of x, y and z in
x+4y-5z = 15+32-60 = -13

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Here is the list of questions asked in campus placement papers for Capgemini Capgemini placement papers for cse. Practice Capgemini Written Test Papers with Solutions and take Q4Interview Capgemini Online Test Questions to crack Capgemini written round test. Overall the level of the Capgemini Online Assessment Test is moderate. Only those candidates who clear the written exam will qualify for the next round, so practic all the questions here and take all the free tests before going for final selection process of Capgemini