Tech Mahindra Written Test Papers
121 / 430
A certain sum of money amounts to Rs. 1008 in 2 years and to Rs.1164 in 3 1/2 years. Find the sum and rate of interests.
A700,13%
B700,15%
C800,13%
D800,15%
Answer: Option C
Explanation:S.I. for 1 and 1/2 years = Rs.(1164-1008) = Rs.156.
SI for 2 years = Rs.(156*(2/3)*2)=Rs.208.
Principal = Rs. (1008 - 208) = Rs. 800.
Now, P = 800, T = 2 and S.l. = 208.
Rate =(100 * 208)/(800 * 2)% = 13%
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122 / 430
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
A100 kmph
B110 kmph
C120 kmph
D130 kmph
Answer: Option C
Explanation:Let speed of the car be x kmph.
Then, speed of the train = (150/100)x = (3/2)x kmph.
=> 75/x - 75/(3/2)x = 125 / (10 * 60)
=> 75/x - 50/x = 5/24.
=> x = (25 x 24)/5 = 120 kmph.
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123 / 430
A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, the how old is B?
A10 years
B5 years
C12 years
D7 years
Answer: Option A
Explanation:Lets assume the age of C = x years
So B's age = 2x
A's age = 2x+2
Given, sum of their (A,B,C) ages = 27 years.
=> x+2x+2x+2 = 27
=> 5x=25
=> x = 5
So, B's age = 10 years.
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124 / 430
In an election between two candidates, one got 55% of the total valid votes, 20% of the votes were invalid. If the total number of votes was 7500, the number of valid votes that the other candidate got, was:
A2700
B2900
C3000
D3100
Answer: Option A
Explanation:Number of valid votes = 80% of 7500 = 6000.
Valid votes polled by other candidate = 45% of 6000
= 45/100 x 6000 = 2700.
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125 / 430
A sum of Rs.150 has two types of coins Rs.1 and Rs.2. If total number of coins is 100 then number of Rs.2 coins is
A50
B45
C65
D40
Answer: Option A
Explanation:Lets assume total no. of 2 coinw = x
so, total no. of 1 coins = (100-x)
=> (100-x) * 2 + x = 150
200 -x = 150
=> x = 50
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126 / 430
Ashok opened a shop investing Rs.60,000 and Madhuri joined him after 2 months investing Rs.90,000. They get a profit of Rs. 1,08,000 after one year. The share of Madhuri is
ARs.35,000
BRs.30,000
CRs.60,000
DRs.45,000
Answer: Option C
Explanation:Ashok and Madhuri ratio = (12 * 60,000) : (10 * 90,000) = 4:5
Madhuri share in profit after 1 year = 1,08,00 * 5/9 = Rs. 60000
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127 / 430
The compound interest on a certain sum for 2 years at 10% per annum is Rs. 525. The simple interest on the same sum for double the time at half the rate percent per annum is:
A400
B500
C600
D800
Answer: Option B
Explanation:Lets assume the sum = Rs. P.
Then, P(1 + 10/100)*(1 + 10/100) - P = 525
P [ (11/10)*(11/10) - 1] = 525
P = (525 x 100)/21 = 2500.
Sum = Rs . 2500.
So, S.I. = Rs. (2500 x 5 x 4)/100 = Rs. 500
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128 / 430
Seats for Mathematics, Physics and Biology in a school are in the ratio 5 : 7 : 8. There is a proposal to increase these seats by 40%, 50% and 75% respectively. What will be the ratio of increased seats?
A2:3:4
B6:7:8
C6:8:9
DNone of these
Answer: Option A
Explanation:Originally, let the number of seats for Mathematics, Physics and Biology be 5x, 7x and 8x respectively.
Number of increased seats are (140% of 5x), (150% of 7x) and (175% of 8x).
=> (140/100) x 5x , (150/100) x 7x and (175/100) x 8x .
The required ratio = 7x : 21x/2 : 14x.
=> 14x : 21x : 28x
=> 2 : 3 : 4.
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129 / 430
A and B can together finish a work 30 days. They worked together for 20 days and then B left. After another 20 days, A finished the remaining work. In how many days A alone can finish the work?
A40
B50
C54
D60
Answer: Option D
Explanation:(A + B)'s 20 day's work = ( 1/30 x 20 ) = 2/3 .
Remaining work = ( 1 - 2/3 ) = 1/3
Now, 1/3 work is done by A in 20 days.
Therefore, the whole work will be done by A in (20 x 3) = 60 days.
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130 / 430
The ratio between the speeds of two trains is 7 : 8. If the second train runs 400 km in 4 hours, then the speed of the first train is:
A70 km/hr
B75 km/hr
C84 km/hr
D87.5 km/hr
Answer: Option D
Explanation:Let the speed of two trains be 7x and 8x km/hr.
Then, 8x = 400/4 = 100
=> x = 100/8 = 12.5.
So, the speed of first train = (7 x 12.5) km/hr = 87.5 km/hr.
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