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Wipro Written Test Papers

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Tot. Mock Test: 24


Total Qs: 362+

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Choose the correct option.

By selling toffees at 20 for a rupee, a man loses 4 %. To gain 20 for one rupee, he must sell


A16 toffees

B20 toffees

C24 toffees

D25 toffees

Answer: Option A

Explanation:

Here is no explanation for this answer

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SHSTTON
7
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20
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A horse and a cow were sold for Rs. 12000 each. The horse was sold at a loss of 20% and the cow at the gain of 20%. The entire transaction resulted in :


Aa. no loss or gain

Bb. loss of Rs. 1000

Cc. gain of Rs. 1000

Dd. gain of Rs. 2000

Answer: Option A

Explanation:

Sp of cow=12000. Sp of horse=12000. Cp of cow=100/120*12000=10000. Similarly for horse cp=15000. Total sp= 24000 and total cp= 25000 loss= 1000

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SHSTTON
7
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A boy was asked to find the value of 7/12 of a sum of money. Instead of multiplying The sum by 7/12 he divided it by 7/12 and thus his answer exceeded the correct Answer By Rs.95. Find the correct answer.


A38

B48

C39

D49

Answer: Option D

Explanation:

Lets assume the sum = x
So as per the ques.
x*12/7 - x*7/12 = 95
x*(144-49) = 84*95
x = 84*95 / 95 = 84.

Therefore, correct answer = 84*7/12 = 49

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NA
SHSTTON
8
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3
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The radius of a sphere is increased by 50%. The increase in surface area of the sphere is :


A100%

B125%

C150%

D200%

Answer: Option B

Explanation:

Take here radius as 100.
So, surface area = 4*22/7*100*100. (Surface area of sphere = 4*pi*r^2)
As per condition:
After increase radius by 50% the new radius = 100+50% of 100=150,
So, new surface area = 4*22/7*150*150
Increase in surface area = ((4*22/7)*150*150 -(4*22/7)*100*100)/(4*22/7-100*100)=125%

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SHSTTON
34
Solv. Corr.
16
Solv. In. Corr.
50
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3 M:44 S
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On increasing the price of T.V. sets by 30%, their sale decreases by 20%. What is the effect on the revenue receipts of the shop ?


A4% increase

B4% decrease

C8% increase

D8% decrease

Answer: Option A

Explanation:

Let, price = Rs.100, sale = 100
Then, sale value = Rs.(100*100)=Rs.10000
New sale value = Rs.(130*80)=Rs.10400
Increase % = 400/10000*100=4%

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SHSTTON
17
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22
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2 men and 3 boys can do a piece of work in 10 days while 3 men and 2 boys can do the same work in 8 days. In how many days can 2 men and 1. boy do the work? .


A5 days.

B12 days.

C12.5 days

DNone of these

Answer: Option C

Explanation:

If 1 day work of a man=m and a boy=b, then
2m + 3b =1/10 ----(i) and
3m + 2b =1/8 ----(ii)
On solving (i) and (ii), m=7/200, b=1/100
So 2 men and 1 boy's 1 day work= (2*7/200)+(1/100)=8/100=2/25
Hence they can complete the work in 25/2=12.5 days

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NA
SHSTTON
9
Solv. Corr.
4
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13
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A polygon has 44 diagonals. Number of sides=?


A7

B11

C8

D9

Answer: Option B

Explanation:

No. of diagonals=[n(n-3)]/2
n=no. of sides
=> 44=(n2-3n)/2
=> n2-3n-88=0
=> n2-11n+8n-88=0
=> n=11

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NA
SHSTTON
23
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19
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A and B undertake to do a piece of work for Rs. 600. A alone can- do it in 6 days while B alone can do it in 8 days. With the help of C, they finish it in 3 days. Find the share of each.


ARs.85

BRs.75

CRs.25

DNone of these

Answer: Option B

Explanation:

C's 1 day's work=1/3 - (1/6 + 1/8)
A:B:C = Ratio of their 1 day's work = 1/6 : 1/8 : 1/24= 4:3:1 (by taking LCM)
therefore,
A's Share = Rs.(600* 4/8) = Rs.300
B's Share = Rs.(600* 3/8) = Rs.225
C's Share = Rs.[600 - (300 + 225)] = Rs.75

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NA
SHSTTON
13
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The average of 5 consecutive numbers is n. If the next two numbers are also included, the average will :


AIncreases by 1

BRemain the same

CIncrease by 1.4

DIncrease by 2

Answer: Option A

Explanation:

let x is first no.
So, x,x+1,x+2,x+3,x+4 are consecutive no.
avg. of this 5 no.
=> (x+x+1+x+2+x+3+x+4)/5=n
x+2=n; n=x+2
As per the question:
Add next 2 no.
so new avg = (x+x+1+x+2+x+3+x+4+x+5+x+6)/7=m
x+3=m ;m=x+3
New avg-Old avg=x+3-x-2=1
Increased by 1

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SHSTTON
12
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The average of four consecutive even numbers is 27. The largest of these numbers is :


A36

B32

C30

D28

Answer: Option C

Explanation:

(x+(x+2)+(x+4)+(x+6))/4=27
=>x=24
so consecutive even numbers are 24,26,28,30

i.e 30 is largest

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