Tech Mahindra Technical Questions in Written Test
111 / 430
A and B invest money in the ratio 3:4 and they has loss of Rs.7000 at the end of year. what is the share of loss of B?
ARs.4000
BRs.3000
CRs.7000
DRs.2000
Answer: Option A
Explanation:Share of loss of B = 7000 *4/7 = Rs. 4000
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112 / 430
At what time between 7 and 8 o'clock the hands of clock will be together?
A23 minutes past 7
B21 1/11 minutes past 7
C38 2/11 minutes past 7
D11 1/11 minutes past 7
ENone of these
Answer: Option C
Explanation:Here is no explanation for this answer
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113 / 430
A number is four less than two times the other number. If their difference is 21, what is the greater number?
A50
B46
C31
D21
Answer: Option B
Explanation:Lets assume two nembers are x and y
first cond.
x=2y-4 --------- (1)
Second cond.
x-y=21 --------- (2)
By solving (1) and (2)
y = 25 and x = 46
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114 / 430
Ten years ago, P was half of Q in age. If the ratio of their present ages is 3:4, what will be the total of their present ages?
A45
B40
C35
D30
Answer: Option C
Explanation:Ratio of their present ages = 3:4
So, the present age of P and Q will be 3x and 4x.
Given, Ten years ago P was half of Q in age.
=> (3x - 10) = (4x - 10)/2
=> 6x - 20 = 4x - 10
=> 2x = 10
=> x = 5
So, Total of their present ages = (3x + 4x) = 7x = 7*5 = 35
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115 / 430
Rahul went to a shop and bought things worth Rs. 25, out of which 30 Paise went on sales tax on taxable purchases. If the tax rate was 6%, then what was the cost of the tax free items?
ARs 15
BRs 12.10
CRs 19.70
DRs 16.80
Answer: Option C
Explanation:Lets assume the cost of the tax items = Rs. x
Cost of tax items, x*(6/100) = 30/100
=> x = Rs. 5
Now non taxable item = (total cost - cost for taxable item - tax)
= (25 - 5 - 0.30) = Rs. 19.70
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116 / 430
The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:
A15
B16
C18
D25
Answer: Option B
Explanation:Lets assume the cost price of 1 article = z.
So, the cost price of 20 article = 20z. -------------- (1)
Selling Price of 20 articles = (20z + 25% of 20z) = 25z.
So, Selling Price of 1 article = 25z/20 = (5/4)*z
=> Selling Price of x articles = (5/4)*z*x -------------- (2)
Given that Selling Price (S.P.) of x articles = Cost Price (C.P.) of 20 articles.
By solving eq. (1) and (2)
so, (5/4)*z*x = 20z.
=> x = 16.
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117 / 430
A1, A2 and A3 enter into a partnership in the ratio 7/2 : 4/3 : 6/5 . After 4 months, A1 increases his share 50%. If the total profit at the end of one year be Rs. 21,600, then A2's share in the profit is:
A2100
B2400
C3600
D4000
Answer: Option D
Explanation:Ratio of initial investments = 7/2 : 4/3 : 6/5
= 105 : 40 : 36.
Let the initial investments be 105x, 40x and 36x.
=> A1 : A2 : A3 = 105x * 4 + 150/100 * 105x * 8 : (40x * 12) : (36x * 12)
= 1680x : 480x : 432x
= 35 : 10 : 9.
Hence, A2's share = Rs. 21600 x 10/54 = Rs. 4000.
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118 / 430
If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:
A50 km
B56 km
C70 km
D80 km
Answer: Option A
Explanation:Let the actual distance travelled be x km.
Then, x/10 = (x + 20)/14.
=> 14x = 10x + 200
=> 4x = 200.
=> x = 50 km.
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119 / 430
4 men and 6 women can complete a work in 8 days, while 3 men and 7 women can complete it in 10 days. In how many days will 10 women complete it?
A35
B40
C45
D50
Answer: Option B
Explanation:Let 1 man's 1 day's work = x and 1 woman's 1 day's work = y.
Then, 4x + 6y = 1/8 and 3x + 7y = 1/10.
Solving the two equations, we get: x = 11/400, y = 1/400.
So, 1 woman's 1 day's work = 1/400.
10 women's 1 day's work = 1/400 x 10 = 1/40.
Hence, 10 women will complete the work in 40 days.
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120 / 430
Two numbers are respectively 20% and 50% more than a third number. The ratio of the two numbers is:
A2:5
B3:5
C4:5
D5:3
Answer: Option C
Explanation:Lets assume the third number = x
Then, first number = 120% of x = 120x/100 = 6x/5
Second number = 150% of x = 150x/100 = 3x/2
Ratio of first two numbers = 6x/5 : 3x/2 = 12x : 15x = 4 : 5
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