iGate aptitude questions for freshers
101 / 349
The average age of 5 girls is 7. The oldest among them is 15 years ol What is the average age of others?
A5.5 Years
B6 Years
C5 Years
D4 Years
Answer: Option C
Explanation:sum of ages of girls = 35
sum of ages of rest of 4 girls=20
So, Average = 20/4 = 5
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102 / 349
An isosceles triangle whose side are 13cm, 13cm, 10cm, is inscribed in a circle. Find the radius of circle
A6 cm
B7 cm
C7.04cm
D8 cm
Answer: Option C
Explanation:a=13,b=13,c=10
s =(a+b+c)/2 = (13+13+10)/2=18
area of triangle=[18(18-13)(18-13)(18-10)]^1/2 = (18*5*5*8)^(1/2) =60 cm^2
let R be the radius,then
R=(a*b*c)/(4*area of triangle)
R=(13*13*10)/(4*60)= 7.04cm
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103 / 349
How many 1/15 are there in 243/5 ?
A429
B529
C629
D729
Answer: Option D
Explanation:Here is no explanation for this answer
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104 / 349
If 3 numbers are in the ratio of 3:2:5 such that sum of their squares is equal to 1862. what is the middle number?
A25
B14
C30
D34
Answer: Option B
Explanation:Let the numbers are 3x, 2x, 5x
Now,
(3x)^2 + (2x)^2 + (5x)^2 = 1862
=> x^2 = 49
=> x = 7
middle number is 2x = 2 * 7 = 14
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105 / 349
In a school the ratio of boys and girls are in the ration 5:6 .25% of boys will get scholar ship and 20% of girls will get scholar ship what % of students wont get scholarship?
A67%
B87%
C78%
D77%
Answer: Option C
Explanation:Boys : Girls => 5x : 6x
Total no. of students including boys nd girls = 5x+6x = 11x
25% of boys => 5x*25/100 = 5x/4
20% of girls => 6x*20/100 =6x/5
No. of students who are getting scholarship => 5x/4 + 6x/5 = 49x/20
No. of students who are not getting scholarship = 11x - 49x/20 = 171x/20
% of students not getting scolorship => 171x/20/11x * 100
=> 100*171x/220x
= 77.7% ~ 78%
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106 / 349
In a particular library there are 5 computer clusters open for public use. Each Computer Clusters has 40 Tablets. In the 1st week, 75 tablets are used, while 155 tablets are used in the second week, 30 in the third week & 140 in 4th week. Approximately what fraction of the library's computer facilities are in use per month?
A1/3
B1
C1/2
DNone of these
Answer: Option C
Explanation:Total number of tablets = 40*5 = 200
Fraction of library's computer facilities used,
1st week = 75/200 = 3/8
2nd week = 155/200 = 31/40
3rd week = 30/200 = 3/20
4th week = 140/200 = 7/10
Fraction of library's computer facilities used per month
= (3/8+31/40+3/20+7/10)/4
= 1/2
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107 / 349
In how many ways can the letter form HARDWARE do not vowels come together.
A8600
B9500
C6000
D9000
Answer: Option D
Explanation:Total no of words make from HARDWARE = 8!/2!*2! = 10080
Vowels come together = 6!/2!*3!/2! = 1080
vowels nt cmg together = 8!/2!*2!-6!/2!*3!/2! = 9000
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108 / 349
If 15 men can dig a pit of 35 cu units in 7 days. How many men can dig a pit of 65 cu units in 5 days?
A40 Men
B20 Men
C43 Men
D39 Men
Answer: Option D
Explanation:m1*t1*w2=m2*t2*w1
m2=(m1*t1*w2)/(w1*t2)
m2=(5*7*65)/(35*5)=39 men
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109 / 349
A factory produces 1 defective bulb out of 10 bulbs a yr. if it produces 870 bulbs a year, how many defective bulbs are produced?
A78
B90
C87
D80
Answer: Option C
Explanation:10 out of 1 is defective
20 out of 2 is defective
100 out of 10 is defective
and so on
800 out of 80 is defective
70 out of 7 is defective
80+7=87
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110 / 349
If a circle with radius 6 cm and other circle with radius 8 cm and their centers are separated by 10 cm then what is the chord length?
A2
B6
C8.2
D9.6
EData Insuficient
Answer: Option D
Explanation:Draw two circles asper the given data(form a triangle with sides 10,8,6)
s = (10+8+6)/2 = 12
Area = ?{12(12-10)(12-8)(12-6)} = 24
Let the height of the triangle(which is half of the chord)=h
1/2 *10*h=24
=> h=4.8
Hence length of the chord=2*4.8=9.6
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