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iGate aptitude questions for freshers

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Tot. Mock Test: 11


Total Qs: 349+

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23
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The average age of 5 girls is 7. The oldest among them is 15 years ol What is the average age of others?


A5.5 Years

B6 Years

C5 Years

D4 Years

Answer: Option C

Explanation:

sum of ages of girls = 35
sum of ages of rest of 4 girls=20
So, Average = 20/4 = 5

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SHSTTON
0
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5
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An isosceles triangle whose side are 13cm, 13cm, 10cm, is inscribed in a circle. Find the radius of circle


A6 cm

B7 cm

C7.04cm

D8 cm

Answer: Option C

Explanation:

a=13,b=13,c=10

s =(a+b+c)/2 = (13+13+10)/2=18

area of triangle=[18(18-13)(18-13)(18-10)]^1/2 = (18*5*5*8)^(1/2) =60 cm^2

let R be the radius,then
R=(a*b*c)/(4*area of triangle)

R=(13*13*10)/(4*60)= 7.04cm

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SHSTTON
3
Solv. Corr.
3
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6
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How many 1/15 are there in 243/5 ?


A429

B529

C629

D729

Answer: Option D

Explanation:

Here is no explanation for this answer

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NA
SHSTTON
31
Solv. Corr.
10
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41
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104 / 349

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If 3 numbers are in the ratio of 3:2:5 such that sum of their squares is equal to 1862. what is the middle number?


A25

B14

C30

D34

Answer: Option B

Explanation:

Let the numbers are 3x, 2x, 5x
Now,
(3x)^2 + (2x)^2 + (5x)^2 = 1862
=> x^2 = 49
=> x = 7
middle number is 2x = 2 * 7 = 14

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NA
SHSTTON
7
Solv. Corr.
14
Solv. In. Corr.
21
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In a school the ratio of boys and girls are in the ration 5:6 .25% of boys will get scholar ship and 20% of girls will get scholar ship what % of students wont get scholarship?


A67%

B87%

C78%

D77%

Answer: Option C

Explanation:

Boys : Girls => 5x : 6x
Total no. of students including boys nd girls = 5x+6x = 11x
25% of boys => 5x*25/100 = 5x/4
20% of girls => 6x*20/100 =6x/5
No. of students who are getting scholarship => 5x/4 + 6x/5 = 49x/20
No. of students who are not getting scholarship = 11x - 49x/20 = 171x/20
% of students not getting scolorship => 171x/20/11x * 100
=> 100*171x/220x
= 77.7% ~ 78%

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SHSTTON
2
Solv. Corr.
2
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In a particular library there are 5 computer clusters open for public use. Each Computer Clusters has 40 Tablets. In the 1st week, 75 tablets are used, while 155 tablets are used in the second week, 30 in the third week & 140 in 4th week. Approximately what fraction of the library's computer facilities are in use per month?


A1/3

B1

C1/2

DNone of these

Answer: Option C

Explanation:

Total number of tablets = 40*5 = 200

Fraction of library's computer facilities used,
1st week = 75/200 = 3/8
2nd week = 155/200 = 31/40
3rd week = 30/200 = 3/20
4th week = 140/200 = 7/10

Fraction of library's computer facilities used per month
= (3/8+31/40+3/20+7/10)/4
= 1/2

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NA
SHSTTON
5
Solv. Corr.
4
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9
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In how many ways can the letter form HARDWARE do not vowels come together.


A8600

B9500

C6000

D9000

Answer: Option D

Explanation:

Total no of words make from HARDWARE = 8!/2!*2! = 10080
Vowels come together = 6!/2!*3!/2! = 1080
vowels nt cmg together = 8!/2!*2!-6!/2!*3!/2! = 9000

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NA
SHSTTON
2
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0
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If 15 men can dig a pit of 35 cu units in 7 days. How many men can dig a pit of 65 cu units in 5 days?


A40 Men

B20 Men

C43 Men

D39 Men

Answer: Option D

Explanation:

m1*t1*w2=m2*t2*w1
m2=(m1*t1*w2)/(w1*t2)
m2=(5*7*65)/(35*5)=39 men

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SHSTTON
11
Solv. Corr.
10
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21
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A factory produces 1 defective bulb out of 10 bulbs a yr. if it produces 870 bulbs a year, how many defective bulbs are produced?


A78

B90

C87

D80

Answer: Option C

Explanation:

10 out of 1 is defective
20 out of 2 is defective
100 out of 10 is defective
and so on
800 out of 80 is defective
70 out of 7 is defective
80+7=87

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NA
SHSTTON
1
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4
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If a circle with radius 6 cm and other circle with radius 8 cm and their centers are separated by 10 cm then what is the chord length?


A2

B6

C8.2

D9.6

EData Insuficient

Answer: Option D

Explanation:

Draw two circles asper the given data(form a triangle with sides 10,8,6)
s = (10+8+6)/2 = 12
Area = ?{12(12-10)(12-8)(12-6)} = 24
Let the height of the triangle(which is half of the chord)=h
1/2 *10*h=24
=> h=4.8
Hence length of the chord=2*4.8=9.6

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