Mu-Sigma Aptitude Questions and Answers for Freshers
1 / 25
Which letter should be in place of question mark
B C D
A E C
F A ?
AB
BC
CA
DD
Answer: Option A
Explanation:A=1,B=2,C=3--------z=26
so now B+C+D= 2+3+4=9
A+E+C = 1+5+3 = 9
So, F+A+? = 9
=> 6+1+? = 9
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2 / 25
1/4th of 1/2 of 3/4th of 52000 = ?
A4875
B4875
C4857
D4785
E4877
Answer: Option A
Explanation:Here is no explanation for this answer
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3 / 25
Two goats are tied with a rope of length 40m outside of a rectangular shed of dimensions 50m X 30m. The goats are tied to different corners which lie on the opposite ends of a diagonal of the shed. What is the area in which the two goats can eat grass, if they choose not to eat in the common approachable area?
A1200pi
B1225pi
C2400pi
D2450pi
Answer: Option D
Explanation:Given rope of length = 40m (radius)
Area of semi circle =(pi*r^2)/2 = (1600 * pi)/2 = 800*pi ---(1)
Area of quarter circle = (1/2 * 800 * pi) = 400*pi ----- (2)
Area of sector is = r*r*(pi/2)/2 = 25*pi ----- (3)
By adding above eq. (1) (2) & (3)
Total area = 1225*pi
As per quesiton there are 2 goats
so area = 1225*pi*2 = 2450pi
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4 / 25
In a society of 80 resident families who subscribe newspapers, 60% of them subscribe The Hindu newspaper, 80% of them subscribe regional language newspaper and 70% of them subscribe TOI. How many families could, at the least, be subscribing to all the three newspapers
A0%
B5%
C10%
D20%
Answer: Option C
Explanation:Total no. of families who take newspaper=80
Hindu newspaper = 60% = (80*60/100) = 48
Regional newspaper = 80% = (80*80/100) = 64
TOI newspaper = 70% = (70*80/100) = 56
Find common families take H.C.F (48,64,56) = 8
Therefore,(8/80)*100=10%
So, common families who take all newspaper = 10%.
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5 / 25
What is the simplified result of following the steps below in order?
A3-X
BX+2
CX-3
DX2-x-6
Answer: Option D
Explanation:X2-X-6=0
(x-3)(X+2)=0
X=3,-2
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6 / 25
if a=2,b=4,c=5 then (a+bc)/(ca+b)
A1
B11/30
C0
D-11/30
E-1
Answer: Option A
Explanation:Here is no explanation for this answer
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7 / 25
A father is 30 years older than his son however he will be only thrice as old as the son after 5 years what is father's present age ?
A40 yrs
B30 yrs
C50 yrs
DNone of these
Answer: Option A
Explanation:Lets assume son's age = x
So, father's age = x + 30
After 5 years:
Son's age = x + 5
Father's age = x + 35
In 5 years the father is thrice as old as his son so:
3(x + 5) = x + 35
x = 10
So, current father's age = 40 Years.
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8 / 25
A person travels in a car with uniform speed. He observes the milestone,which has 2 digits. After one hour he observes another milestone with same digits reversed. After another hour he observes another milestone with same 2 digits separated by 0. Find the speed of the car?
A40 Kmph
B55 Kmph
C50 Kmph
D45 Kmph
Answer: Option D
Explanation:Let 10'splace digit is x and unit's place digit y
First milestone : 10x+y
Second milestone : 10y+x
Third milestone: 100x+y
Since the speed is uniform so
Distance covered in first Hr = Distance covered in Second Hr
(10y+x)-(10x+y) = (100x+y)-(10y+x)
By solving,
y=6x
but since x and y are digits so only possible combination is x=1 and y=6,
So average speed = 45 Kmph
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9 / 25
If log 0.317=0.3332 and log 0.318=0.3364 then find log 0.319 ?
A0.3396
B0.4396
C0.5396
DNone of these
Answer: Option A
Explanation:log 0.317=0.3332 and log 0.318=0.3364
then
log 0.319=log0.318+(log0.318-log0.317)
=0.3396
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10 / 25
There are 8 people, F, G, H, J, K, L, M, and N. 2 groups are to be formed. F will always go with J. G and M will never go together. H will always go with L. N will always go with G. What are the two groups to be formed?
A1st Way Group 1: F, J, G, N Group 2: M, N, H, L 2nd Way Group 1: F, J, M, K Group 2: G, K, H, L
B1st Way Group 1: F, J, G, N Group 2: M, K, H, L 2nd Way Group 1: F, J, N, K Group 2: G, N, H, L
C1st Way Group 1: F, J, G, N Group 2: M, K, H, L 2nd Way Group 1: F, J, M, K Group 2: G, N, H, L
DNone of these
Answer: Option C
Explanation:8 people namely F,G,H,J,K,L,M,and N respectively.
Now we have to form 2 groups
1st condition: F will always go with J
Meaning: F and J always lie in same group. ............(i)
2nd condition:G and M will never go together.
Meaning: G and M always lie in different groups. .........(ii)
3rd condition:H will always go with L.
Meaning:H and L always lie in same group. .............(iii)
4th condition:N will always go with G.
Meaning:N and G always lie in same group. ..........(iv)
According to (i),(ii),(iii),and (iv)
2 groups can be formed in following 2 ways
1st Way
Group 1: F, J, G, N
Group 2: M, K, H, L
2nd Way
Group 1: F, J, M, K
Group 2: G, N, H, L
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