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1 / 33
If A alone can do a piece of work in 8 days and B alone can do the same work in 12 days. How many days A and B required to finish the same work if they work togather?
A24/5 days
B24 days
C5day days
D5/24 days
ENone of these
Answer: Option A
Explanation:A alone one day work = 1/8
B alone one day work = 1/12
Both A and B one day work = (1/8 + 1/12) = (3/24 + 2/24)
= 5/24
so A and B together finish the work in 24/5 day
or 4 4/5 days.
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2 / 33
Three solid metallic balls of radii, 3 cm, 4cm and 5 cm are melted and moulded into a single solid ball. The radius of the new ball is
A3 cm
B4 cm
C5 cm
D6 cm
ENone of above
Answer: Option D
Explanation:Total volume of three metallic balls(spheres)= (4/3)*Pi*(3^3+4^3+5^3)
=(4/3)*Pi*216= Volume of new ball with radius 'r'
so (4/3)*Pi*r^3=(4/3)*Pi*216
r^3=216 , r=6
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3 / 33
A, B and C enter into a partnership and their shares are in the ratio 1/2:1/3:1/4. After 2 months, A withdraws half of his capital and after 10 months, a profit of Rs. 378 is divided among them. What is B’s share?
ARs .129
BRs. 144
CRs. 156
DRs. 168
Answer: Option B
Explanation:Ratio of investment = 1/2 : 1/3 : 1/4,
taking lcm of (2,3,4) and divide by this ratio's we get 6 : 4 : 3,
we have to assume there initial investment is 6x, 4x and 3x
now we can write A : B : C = (6x * 2 + 3x*10) : (4x *12) : (3x*12) after doing calculation we got
= 42:48:36 more simplify it
= 7:8:6
now we need to calc B'share = (8/21) * 378 = 144
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4 / 33
Divide 45 into four parts such that when 2 is added to the first part, 2 is subtracted from the second part, 2 is multiplied by the third part and the fourth part is divided by two, all result in the same number.
A8, 12, 5, 20
B6,10,15,11
C2,8,14,9
DNone of these
Answer: Option A
Explanation:If x is common result, then numbers are 2x, x/2, x+2, x-2
and
2x+ x/2+ x+2+x-2 = 45
4x+x/2 =45
9x =90
x=10
hence numbers are
8,12,5,20
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5 / 33
Few years ago on 31st January on her 26th birthday a lady laid a baby. Now what's the sum of their ages?
A37
B38
C43
D51
Answer: Option B
Explanation:All other options have thier unit place digit odd while we require even digit
because before x years she laid a baby. That time she is 26years old
So, now sum of thier ages is 26 + 2x. The total should be even number.
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6 / 33
What will be the value of x^(1/2).x^(1/4).x^(1/8)............to infinty.
Ax^2
Bx
Cx^(3/2)
Dx^3
Answer: Option B
Explanation:x^(1/2+1/4+1/8.infinite )so x^(1/2(1+1/2+1/4+.....))
=x^(1/2(1/(1-1/2))....................infinite terms formula a/1-r for a+ar+.....
=x^1
=x
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7 / 33
A and B are partners in a business. A contributes 1/4 of the capital for 15 months and B received 2/3 of the profit .For how long B’s money was used.
A6 months
B9 months
C10 months
D1 year
Answer: Option C
Explanation:B received 2/3 of the profit
A : B = 1 : 2
Let the total capital = x
Then A's capital = x/4
B's capital = x – x/4 = 3x/4
Assume B's money was used for b months
Then A:B = (x/4)*15 : (3x/4)*b = 1 : 2
15/4 : 3b/4 = 1 : 2
15 : 3b = 1 : 2
5 : b = 1 : 2
5/b = 1/ 2
b = 5*2 = 10 months
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8 / 33
In seven given numbers,the average of first four numbers is 4 and that of last four numbers is also 4. If the average of these seven numbers is 3, the fourth number is?
A3
B4
C7
D11
Answer: Option D
Explanation:let 7 numbers are a,b,c,d,e,f,g.
given avg of first 4 nums are 4...i.e (a+b+c+d)/4=4
a+b+c+d=16
given avg of last 4 nums are also 4..i.e.(d+e+f+g)/4=4
d+e+f+g=16
e+f+g=16-d
given avg of 7 nums are 3....i.e (a+b+c+d+e+f+g)/7=3
a+b+c+d+e+f+g=21
16+16-d=21
d=32-21
d=11
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9 / 33
The boys and girls in a college are in the ratio 3 : 2. If 20% of the boys and 25% of the girls are adults, the percentage of students who are not adults is :
A58%
B67.50%
C78%
D82.50%
Answer: Option C
Explanation:let total students will be 100 divide it in 3:2 =60/40
20 % 60=12 boys adult
25 % 40= 10girls adults
total adults = 22
no of students =100
100-22=78
78% are non adult
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10 / 33
What was the day of the week on 12th January, 1979?
AFriday
BSunday
CWednesday
DMonday
Answer: Option A
Explanation:First Split the given date:1978 + 12th january 1979
1978=1600+300+78
1600years has 0 odd days
300years has 1 odd days
In 78 years has a 19 leap years and 59 nonleap years.
19*2=38
59*1=59
In january has 12 odd days
so total odd days are=1+38+59+12=110
110%7=5(remainder)
so 5->Friday
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