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C Programming :: Pointers

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9. What is the output of the following C Program?

#include
int main(){
void *vp;
char ch = 'g', *cp = "goofy";
int j '= 20;
vp = &ch;
printf("%c", *(char *)vp);
vp = &j;
printf("%d",*(int *)vp);
vp = cp;
printf("%s",(char *)vp + 3);
}

Answer: Option B

Explanation :

Since a void pointer is used it can be type casted to any other type pointer. vp = &ch stores address of char ch and the next statement prints the value stored in vp after type casting it to the proper data type pointer. the output is "g".
Similarly the output from second printf is "20". The third printf statement type casts it to print the string from the 4th value hence the output is "fy".

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