#define FALSE -1 #define TRUE 1 #define NULL 0 int main() { if(NULL) puts("NULL"); else if(FALSE) puts("TRUE"); else puts("FALSE"); } - Q4Interview" /> #define FALSE -1 #define TRUE 1 #define NULL 0 int main() { if(NULL) puts("NULL"); else if(FALSE) puts("TRUE"); else puts("FALSE"); } - Q4Interview" />
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C Programming :: C Preprocessor

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6. What will be output of the following "c" code?

#include
#define FALSE -1
#define TRUE 1
#define NULL 0
int main() {
if(NULL)
puts("NULL");
else if(FALSE)
puts("TRUE");
else
puts("FALSE");
}

Answer: Option B

Explanation :

Preprocessor doesn't replace the values given inside the double quotes. The check by if condition is boolean value false so it goes to else. In second if -1 is boolean value true hence "TRUE" is printed.

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