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C Programming :: String

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4. int main()
{
char string[]="Hello World";
display(string);
return 0;
}
void display(char *string)
{
printf("%s",string);
}

Answer: Option E

Explanation :

In third line, when the function display is encountered, the compiler doesn't know anything about the function display. It assumes the arguments and return types to be integers, (which is the default type). When it sees the actual function display, the arguments and type contradicts with what it has assumed previously. Hence a compile time error occurs.

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