int main() { int i=5,j=6,z; printf("%d",i+++j); return 0; } - Q4Interview" /> int main() { int i=5,j=6,z; printf("%d",i+++j); return 0; } - Q4Interview" />
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C Programming :: Increment-Decrement

5. What will be output of the following "c" code?

#include
int main()
{
int i=5,j=6,z;
printf("%d",i+++j);
return 0;
}

Answer: Option B

Explanation :

the expression i+++j is treated as (i++ + j)

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