void main() { int i=-1,j=-1,k=0,l=2,m; m = i++ && j++ && k++ || l++; printf("%d %d %d %d %d",i,j,k,l,m); } - Q4Interview" /> void main() { int i=-1,j=-1,k=0,l=2,m; m = i++ && j++ && k++ || l++; printf("%d %d %d %d %d",i,j,k,l,m); } - Q4Interview" />
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C Programming :: Increment-Decrement

1. What will be output of the following "c" code?

#include
void main() {
int i=-1,j=-1,k=0,l=2,m;
m = i++ && j++ && k++ || l++;
printf("%d %d %d %d %d",i,j,k,l,m);
}

Answer: Option A

Explanation :

=>Logical operations always give a result of 1 or 0 .
=> Logical AND (&&) operator has higher priority over the logical OR (||) operator.

So the expression i++ && j++ && k++ is executed first. The result of this expression is 0 (-1 && -1 && 0 = 0)

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