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C Programming :: Declarations and Initializations

2. #include
int main() {
int i,j;
j = 10;
i = j++ - j++;
printf("%d %d", i,j);
return 0;
}

Answer: Option A

Explanation :

4th line of the program says j=10 . 5th line says j means post increment so after that line is executed j value will become 11 but during the execution of the 5th line j value is still 10 so i= 10-10=0



Now in the 5th line itself there has been two times increment of j so final value will be 12.



 

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