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What will be output of the following "c" code?
#include<stdio.h>
#define max(a,b) (a>b?b:a)
#define squre(x) x*x
int main()
{
int i = 2, j = 3, k = 1;
printf ("%d %d", max(i,j), squre(k));
return 0;
}
#include<stdio.h>
#define max(a,b) (a>b?b:a)
#define squre(x) x*x
int main()
{
int i = 2, j = 3, k = 1;
printf ("%d %d", max(i,j), squre(k));
return 0;
}A2 1
B3 2
C3 1
D1 3
Answer: Option (Login/Signup)
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Here, in max(i,j)=max(2,3) or #define max(2,3) we check 2>3? It is not correct so 'a' will be value which is 2 & In square(x)=x*x we will get k*K=1*1=1. So, the final value will be 2 1.
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