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In this question A^B means A raised to the power B. If f(x) = ax^4 - bx^2 + x + 5 and f(-3) = 2, then f(3) =
A1
B-2
C3
D8
Answer: Option (Login/Signup)
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Putting the value of x= -3 in equation ax^4 - bx^2 + x + 5=2 we get 81a=9b
Now putting the values of x=3 again in equation
ax^4 - bx^2 + x + 5
81a-9b + 3 + 5
9b-9b + 3 + 5=8 therefore the answer is 8.
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Putting the value of x= -3 in equation ax^4 - bx^2 + x + 5=2 we get 81a=9b
Now putting the values of x=3 again in equation
ax^4 - bx^2 + x + 5
81a-9b + 3 + 5
9b-9b + 3 + 5=8 therefore the answer is 8.
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