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Arithmetic Aptitude :: progressions

10. A ball dropped from H height and moves 80% of height each time. Total distance covered is

Answer: Option D

Explanation :

First time distance= H
Second time = 80H/100 = 4H/5
similarly third time 80% of 4H/5 = H(4^2)/(5^2)
and so on..
This will lead to infinite terms of geometric progression
i.e H+2*4H/5+2*16H/25..
So, Sum = H+ 2*4H/(5(1-4/5)) = 9H

Asked In :: Accenture

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