# Arithmetic Aptitude :: Time and Distance

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**Discussion**

## 7. A thief steals a car at 2.30 p.m and drives it at 60 kmph. The theft is discovered at 3 p.m and the owner sets off in another car at 75 kmph. When will be overtake the thief.

**Answer:**

**Option D**

**Explanation :**

As Theft is discovered at 3:00pm but Thief stole the car at 2:30.

This means thief covered some distance in this 30 min gap.

Distance travelled by thief in 30 min = 60 * 1/2 = 30 km

Owner Discovered Car at 3:00pm

Now relative speed = (75-60)km/hr = 15km/hr

Time needed to travel 30km by the speed of 15km/hr.

Time at which owner meets thief = 30/15 = 2 hrs

So After 2 hrs (i.e,at 5:00 pm) the owner will catch/overtake the thief