# Arithmetic Aptitude :: Problems on Trains

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## 4. Two trains each 100 m long, moving in opposite directions, cross each other in 8 seconds. If one is moving twice as fast the other, then the speed of the faster train is

**Answer:**

**Option B**

**Explanation :**

speed of the faster train = 2x m/sec.

Relative speed of train = (x + 2x) m/sec = 3x m/sec.

Total distance = (100 + 100)m = 200m

3x = 200/8

=> 24x = 200 => x = 25/3

So speed of the faster train = 2 * 25/3 m/sec

= 50/3 m/sec

= 50/3 * 18/5 = 60 km/hr.

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