Arithmetic Aptitude :: H.C.F and L.C.M
5. Let p and q be two prime numbers such that p is greater than q. If 319 is their LCM then the difference of thrice of q and p is:
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Solution: We know that HCF of two prime numbers is 1.
Product of HCF and LCM = 1 x 319 = 319.
Remember that, Product of two number = Product of their HCF and LCM
pq = 319
Now, co-primes with product 319 are (1,319) and (29,11)
Since p > q, p = 29 and q = 11
Then 3q - p = 3 - 29 = 4.
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