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Choose the correct option.
Find the value of "n" where 3^48 + 3^1996 + 3^3943+33^n is a perfect cube?
A1963
B1964
C1960
D1991
Answer: Option (Login/Signup)
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see subtracting powers of each coefficient 1996-48 = 1948
3943-1996= 1947
similary 3n-3943=1946
solving for n , n comes out to be 1963.
3943-1996= 1947
similary 3n-3943=1946
solving for n , n comes out to be 1963.
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see subtracting powers of each coefficient 1996-48 = 1948
3943-1996= 1947
similary 3n-3943=1946
solving for n , n comes out to be 1963.
3943-1996= 1947
similary 3n-3943=1946
solving for n , n comes out to be 1963.
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