Quantitative Aptitude :: Simplification - Discussion

3x+8y)/( 2y(x/2y - 1))   \\ take 2y as a common

(3x + 8y)/ (2y (1))    \\substitue (x/2y = 2) as in question

3x/2y + 8y/2y

3*2 + 4        \\ substitute (x\2y =2) as per condition

6 + 4

10

3x+8y)/( 2y(x/2y - 1))   \\ take 2y as a common

(3x + 8y)/ (2y (1))    \\substitue (x/2y = 2) as in question

3x/2y + 8y/2y

3*2 + 4        \\ substitute (x\2y =2) as per condition

6 + 4

10

=(3x+8Y)/(x-2y)

According to question..   x/2y=2

therefor, x=4y

=(3*4y+8y)/(4y-2y)

=20y/2y

=10

x/2y=2 => x=4y --------(1)

(3x+8y) / (x-2y)

==> (3(4y)+8y)/ (4y-2 y)   // substituting x value (in eqn 1)

==>  (12y+8y) / (2y)

==> 20y/2y =10  

x/2y=2

then x=4y

therfore (3(4y)+8y)/(4y-2y)=20y/2y=10

The given data is x/2y=2

Then x=4y

Now substitute the x value in (3x+8y)/(x-2y) and

we get (12y+8y)/(4y-2y)

which is equal to 20y/2y

Answer becomes 10

x/2y=2 From this we can say x=4y

Now putting that x value in (3x+8Y)/(x-2Y) we get 20y/2y= 10