# Arithmetic Aptitude :: Problems on Ages

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## 7. Father is aged three times more than his son Mohit. After 8 years, he would be two and a half times of Mohit's age. After further 8 years, how many times would he be of Mohit's age?

**Answer:**

**Option B**

**Explanation :**

Let's assume Monit's present age = X years.

So father's present age = (X + 3X) years = 4X years.

After 8 years.

(4X + 8) =5/2 * (X + 8)

=> 8X + 16 = 5X + 40

=> 3X = 24 so, X=8

Hence, required ratio = (4X + 16) / (X + 16) = 48/24 = 2

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