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What is the output of the following program ?
#include<stdio.h>
void main()
{
printf("sizeof (void *) = %d \n", sizeof( void *));
printf("sizeof (int *) = %d \n", sizeof(int *));
printf("sizeof (double *) = %d \n", sizeof(double *));
printf("sizeof(struct unknown *) = %d \n", sizeof(struct unknown *));
}
#include<stdio.h>
void main()
{
printf("sizeof (void *) = %d \n", sizeof( void *));
printf("sizeof (int *) = %d \n", sizeof(int *));
printf("sizeof (double *) = %d \n", sizeof(double *));
printf("sizeof(struct unknown *) = %d \n", sizeof(struct unknown *));
}Asizeof (void *) = 4 sizeof (int *) = 4 sizeof (double *) = 4 sizeof(struct unknown *) = 4
Bsizeof (void *) = 2 sizeof (int *) = 2 sizeof (double *) = 4 sizeof(struct unknown *) = 4
Csizeof (void *) = 4 sizeof (int *) = 4 sizeof (double *) = 2 sizeof(struct unknown *) = 4
DCompilation Error
Answer: Option (Login/Signup)
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The pointer to any type will have the same size i.e, 4 bytes, be it int or float or double or any type.
Hence, option A is correct.
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