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What is the output of the following 'C' program ?
#include<stdio.h>
#include<math.h>
void main()
{
printf("%f",sqrt (36.0));
}
#include<stdio.h>
#include<math.h>
void main()
{
printf("%f",sqrt (36.0));
}A6
B6
C6
DSome absurd result
Answer: Option (Login/Signup)
Show Explanation
Here, the argument is 36.0, so sqrt() function returns 6.000000, as the return type we want is in float.
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The sqrt() function returns the square root of a given argument.
Here, the argument is 36.0, so sqrt() function returns 6.000000, as the return type we want is in float.
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