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C Programming :: Loop Control

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8. What is the output of the following C Program?

#include
void main()
{
signed char i=0;
for(;i>=0;i++) ;
printf("%d\n",i);
}

Answer: Option D

Explanation :

Notice the semicolon at the end of the for loop. Tee initial value of the i is set to 0.
The inner loop executes to increment the value from
0 to 127 and then it rotates to the negative value of -128.
The condition in the for loop fails and so comes out of the for loop. It prints the current value of i that is -128.

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