Quantitative Aptitude :: Average - Discussion

1. A+B/2=40kg and B+C/2=43kg

2. A+B=80kg and B+C=86kg

3.A+B+C/3=45kg

4. A+B+C=135

5. 80+C=135 and A+86 = 135 {Substituting A+B=80 and B+C=86 in original equation}

6. C=55kg and A=49

7. B+55+49=135

8.B=31kg  {Required Answer}

In mathematics, the Pythagoras theorem, also known as the Pythagoras
theorem, is a fundamental relation in Euclidean geometry between three
sides of a right triangle. This states that the area of   the square
whose side is the hypotenuse is equal to the sum of the squares on the
other two sides.

<br><span style="padding-left:38px;"></span>In a
right-angled triangle, \(Hypotenuse^{2}\) = \(Base^{2}\) +
\(Height^{2}\).

<br><span style="padding-left:38px;"></span>\( \mathbb{iv.} \) The line joining the mid-point of a side of a triangle to the positive vertex is called the <b>median</b>.

<br><span style="padding-left:38px;"></span>\( \mathbb{v.} \) The point where the three medians of a triangle meet, is called <b>centroid</b>. The centroid divided each of the medians in the ratio 2 : 1.

<br><span style="padding-left:38px;"></span>\( \mathbb{vi.} \) In an isosceles triangle, the altitude from the vertex bisects the base.

<br><span style="padding-left:38px;"></span>\( \mathbb{vii.} \) The median of a triangle divides it into two triangles of the same area.

<br><span style="padding-left:38px;"></span>\( \mathbb{viii.} \) The area of the triangle formed by joining the mid-points of the sides of a given triangle is one-fourth of the area of the given triangle.